There is a function which can do it for you. You have to include math.h in headers. And then use the function pow(x, y) which returns a value of type double (x and y are double too).
pow(x, y) = x to the power of y.
Compute means to calculate. What do you want to "compute", if you already know it is 2? If you want to show the value:System.out.println("Your number is " + 2);Compute means to calculate. What do you want to "compute", if you already know it is 2? If you want to show the value:System.out.println("Your number is " + 2);Compute means to calculate. What do you want to "compute", if you already know it is 2? If you want to show the value:System.out.println("Your number is " + 2);Compute means to calculate. What do you want to "compute", if you already know it is 2? If you want to show the value:System.out.println("Your number is " + 2);
i want to write a simple without using pointer or array c program which will print greatest number when i give 20 number .........How far have you gotten so far?
int main (void) { printf ("%ld\n", 365L*24*60*60); } or int main (void) { printf ("%ld\n", 366L*24*60*60); }
This is not a question.
Identification division. Program-id. Quadratic. Environment division. Data division. Working-storage section. 01 a pic 9(3) value 0. 01 b pic 9(3) value 0. 01 c pic 9(3) value 0. 01 d pic 9(3) value 0. 01 e pic 9(3) value 0. 01 f pic 9(3) value 0. 01 g pic 9(3) value 0. 01 h pic 9(3) value 0. 01 x1 pic 9(3) value 0. 01 x pic z(3).z(2) value 0. 01 x2 pic 9(3) value 0. 01 y pic z(3).z(2) value 0. Procedure division. Display "Written by Martin O. Egua, but not complete". Display "Quadratic equation solver for three values a, b & c" Display "Enter a number: " Accept a. Display "Enter the second number: " Accept b. Display "Enter the last number: " Accept c. compute d = (b * b) compute e = 4 * a * c compute f = 2 * a compute g = d - e compute h = function sqrt (g). compute x1 = (-b) + h compute x = x1 / f Display "X = " x compute x2 = (-b) - h compute y = x2 / f Display "Y = " y Display "Send the accurate program". Stop run.
Use Wolfram|Alpha... go to the related link below, Wolfram|Alpha, and type in (is __ (number) prime) and then the program will compute that and tell you if it is prime or composite.
permutation without replacement
Compute means to calculate. What do you want to "compute", if you already know it is 2? If you want to show the value:System.out.println("Your number is " + 2);Compute means to calculate. What do you want to "compute", if you already know it is 2? If you want to show the value:System.out.println("Your number is " + 2);Compute means to calculate. What do you want to "compute", if you already know it is 2? If you want to show the value:System.out.println("Your number is " + 2);Compute means to calculate. What do you want to "compute", if you already know it is 2? If you want to show the value:System.out.println("Your number is " + 2);
nr\m;laeoh9y0m g.qthnedxc In fortran: do i=1,5 write(6,*)i enddo stop end This program will write the numbers 1 to 5 on the screen.
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int factorial(int n) { int i; int f=1; for(i=2;i<=n;++i) f*=i; return f; }
number of miles driven on a tank / number of gallons to replenish that tank.
i want to write a simple without using pointer or array c program which will print greatest number when i give 20 number .........How far have you gotten so far?
You can compute the number of lines in a file using Perl with the following code snippet: my $filename = 'your_file.txt'; # Replace with your file name open(my $fh, '<', $filename) or die "Could not open file '$filename' $!"; my $line_count = 0; $line_count++ while <$fh>; close($fh); print "Number of lines: $line_count\n"; This script opens the specified file, reads through it line by line, increments the line count, and prints the total number of lines.
Compute to the smallest fraction, reduce to the least number
int main (void) { printf ("%ld\n", 365L*24*60*60); } or int main (void) { printf ("%ld\n", 366L*24*60*60); }
you read the book how to solve by dromy.