CLS
PRINT "PROGRAM: Calculate both perimeter/area of rectangle"
INPUT " Length"; length
INPUT "Breadth"; breadth
PRINT "Perimeter: "; 2 * (length + breadth)
PRINT " Area: "; length * breadth
END
Remember that the area of a rectangle is width * height: static int getArea(Rectangle r) { return r.width * r.height; }
To write a geometric C program, start by including the necessary header files, such as <stdio.h> for input and output. Define functions for calculating geometric properties, like area and perimeter, for different shapes (e.g., circle, rectangle). In the main() function, prompt the user for shape dimensions, call the appropriate functions, and display the results. Ensure proper handling of user inputs and include necessary validations for a robust program.
2. Write a program using switch statement that reads a character representing a geometrical figure, then asks the user to enter the required data (ex. Radius for a circle, length and height for a rectangle, etc. ...) . The program should then print the area and circumference.Figures are: circle(c), square(s), rectangle(r), triangle (t).
By using that one thing.
Write a program that calculates the area of a triangle in QBASIC
#include<stdio.h> void main() { float length, breadth, area, perimeter; printf("Enter the length & breadth of a Rectangle\n(length breadth): "); scanf("%f %f",&length,&breadth); area=length*breadth; perimeter=2*(length+breadth); printf(" Area of the Rectangle=%0.3f\n",area); printf("Perimeter of the Rectangle=%0.3f\n",perimeter); printf("(Press ENTER to exit.)"); getch(); printf("\n"); }
Write two simultaneous equations and solve them. One for the perimeter, one for the area.
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.
No. For example, a 4x1 rectangle will have an area of 4 and a perimeter of 10. A 2x2 rectangle will have the same area of 4, but a perimeter of 8.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
The perimeter of the rectangle is the sum of its 4 sides.
find the perimeter and area of a rectangle that is 15cm long and 5cm wide
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.