How do you write a program to find the length of a string?

Answer 1

/* with run-time library */

int len;

char* str;

len = strlen (str);

/* without run-time library */

int mystrlen (const char* str) {

int len;

while (*str != '\0') {

len++;

str++;

}

return len;

}

int len;

char* str;

len = mystrlen(str);

Answer 2

char* cString = "Hello World!";

int length;

for (length = 0; cString[length]; ++length);

//length now holds the length of cString

else try this out!!!!!!

#include<conio.h>

#include<stdio.h>

void main()

{

char a[20];

int i;

clrscr();

gets(a);

i=0;

while(a[i]!='\0')

i++; //counts no of chars till encountering null char

printf(string length=%d,i);

getch();

}

Answer 3

#include<iostream.h>

#include<conio.h>

#include<stdio.h>

void main()

{

clrscr();

int c=1;

int i=0;

int b;

char d[10];

cout<<"Enter the string";

gets(d);

while(d[i]!='\0')

{

b=c++;

i++;

}

cout<<"Length"<<b;

getch();

}

***********************************************

#include<stdio.h>

#include<conio.h>

void main()

{

char a[20];

int i;

clrscr();

printf("Enter the string:");

scanf("%s",a);

for(i=0;i<20;i++)

{

if(a[i]=='\0')

{

printf("string length is:%d",i);

break;

}

}

getch();

}

***************************************************

#include<stdio.h>

#include<conio.h>

void main()

{

char a[20];

int i=0;

clrscr();

printf("Enter the string:");

scanf("%s",a);

while(a[i]!='\0')

{

i++;

}

printf("string length is:%d",i);

getch();

}

Answer 4

#include <windows.h> #include <stdio.h> void main() { CHAR szTest[32] = {"The Quick Brown Fox"}; size_t thelen = strlen(szTest); printf("The length of the string is %d characters\n",thelen) }

Answer 5

Ellipses (...) are used to show indentation for clarity.

int mystrlen(const char *p) {

... int len = 0;

... while (*p++ != '\0') len++;

... return len;

}

or (quicker):

size_t mystrlen(const char *p) {

... const char *q= p-1;

... while ((*++q)!= '\0');

... return q-p;

}

Answer 6

int size(const char *p) { int i; for (i=0; p[i] != '\0'; i++); return i; }

Answer 7

int strlen(const char* str) {

int len;

for (len=0; *str++ != '\0'; len++);

return len;

}

Answer 8

size_t mystrlen (const char *s)

{

register const char *t= s-1;

while (*++t);

return t-s;

}

Answer 9

size_t Strlen (char* pstr) {

size_t len = 0;

while (*pstr++) len++;

return len;

}