I don't program in just C (I use C++) so you may have to change some of the code:
int main()
{
int n;
int last = 1;
int slast = 0;
int numbers[n];
numbers[0] = 1;
for(int i = 1; i < n; i++)
{
numbers[i] = last + slast;
slast = last;
last = numbers[i];
}
return 0;
}
int n needs to be set to however many Fibonacci numbers you want to make.
int last is the last number in the sequence (so far)
int slast is the second last number in the sequence (so far)
int numbers[n] is the int array which holds your numbers
int i is the count for the loop, it is set to 1 because before the loop, I set numbers[0] to 1
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
Step 1. Learn the word "Fibonacci"...
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }
In c: int fibr(int n) { // Find nth Fibonacci number using recursion. if (n<=2) return 1; // the first two Fibonacci numbers are 1 and 1 return (fibr(n-2)+fibr(n-1)); } int fibi(int n) { // Find nth Fibonacci number using iteration. int temp,last=1,f=1; int i; for (i=3;i<n;++i) { // the first two Fibonacci numbers are 1 and 1 temp=f; f+=last; last=temp; } return f; }
write a lex program to delete space from the program
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
write a c program to accept a number and generate a square root cube and exponential values
Exactly what do you mean by 'C program in Java'
Step 1. Learn the word "Fibonacci"...
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }
In c: int fibr(int n) { // Find nth Fibonacci number using recursion. if (n<=2) return 1; // the first two Fibonacci numbers are 1 and 1 return (fibr(n-2)+fibr(n-1)); } int fibi(int n) { // Find nth Fibonacci number using iteration. int temp,last=1,f=1; int i; for (i=3;i<n;++i) { // the first two Fibonacci numbers are 1 and 1 temp=f; f+=last; last=temp; } return f; }
write a lex program to delete space from the program
write an assembly language program to find sum of N numbers
I don't believe that 50 perfect numbers have ever been found, last time I checked there were only about 47 known perfect numbers. It would also require an extremely powerful computer.
#include<iostream> unsigned fib (unsigned term, unsigned a=0, unsigned b=1) { if (term<1) return a; return fib (--term, a+b, a); } int main() { std::cout << "Fibonacci (1000th term): " << fib (1000) << std::endl; }
//to generate Fibonacci series upto a range of 200....(in C).... #include<stdio.h> main() { int a,b,c,i; a=0; b=1; printf("\n FIBONACCI SERIES .....\t"); i=1; while(i<=(200-2)) { c=a+b; printf("\t%d",c); a=b; b=c; i++; } }
I did this as an answre to some common js questions , the question wasWrite a function which will return you first two times 1, then 2, then 3, then 5 and so on (Fibonacci numbers). Don't use any global variables.var fibonacci = (function () {var arr = [0, 1];return function () {var num = arr[arr.length - 1],len = arr.length;arr.push(arr[len - 1] + arr[len - 2]);return num;};}());//testvar i;for (i = 0; i < 10; i++) {console.log(fibonacci());}//1,1,2,3,5,8,13,21,34,55