To write a C++ program to display the student details using class and array of
object.
Sort the array then traverse the array, printing the element values as you go.
Accept 5 numbers in an array and display it.
import java.util.Arrays; import java.util.Scanner; public class Answers { public static void main(String[] args) { //Creates a scanner object named console. Scanner console = new Scanner(System.in); //Variabels int [] numbers = new int [10]; double avg = 0.0; double median = 0.0; int max = numbers[0]; double count = 0.0; //User input. for (int i = 0; i < numbers.length; i++){ System.out.print("Number: "); numbers[i] = console.nextInt(); } //break System.out.println("==============="); //finds the average and max value. for (int i = 0; i < numbers.length; i++){ count += numbers[i]; avg = count / numbers.length; //average if (numbers[i] > max){ //finds the max value. max = numbers[i]; } } median = (numbers[4] + numbers[5])/2; //Median value //Display to user. System.out.println("Highest value found: " + max); //Show maximum value found in array System.out.printf("Median is: %.3f \n",median); //Show median System.out.printf("Average is: %.3f \n",avg); //Show average sortAsc(numbers); //Print out whole array ascending } //Method for sorting an Array ascending. public static void sortAsc(int [] array){ for (int i = 0; i < array.length; i++){ Arrays.sort(array); System.out.println(array[i]); } } } This should do everything you asked for, hope this helps!
find even number in array
Using sorted(array,reverse=True)
Sort the array then traverse the array, printing the element values as you go.
I know how to do this and you need to know how to do this. Why don't you do your best at writing this program and if it does not work then ask for help. You will not learn anything if I give you the answer.
sorry
the following program will display all numbers given in the array in ascending order #include<stdio.h> void main() { int i,h,p; int numbers[10]={5,8,3,2,6,7,9,4,1,10}; for(p=0;p<=8;p=p+1) { for(i=0;i<=8;i=i+1) { if(numbers[i]>numbers[i+1]) { a=numbers[i]; numbers[i]=numbers[i+1]; numbers[i+1]=a; } } } for(i=0;i<=9;i=i+1) { printf("%d ",numbers[i]); } }
Accept 5 numbers in an array and display it.
To sort numbers in ascending order in VBScript, you can use an array and the built-in Sort method of a Dictionary object. First, store the numbers in an array, then add them to a Dictionary and sort the keys. Finally, you can loop through the sorted keys to retrieve the numbers in ascending order. Here's a simple example: Dim numbers numbers = Array(5, 2, 9, 1, 3) Set dict = CreateObject("Scripting.Dictionary") For Each num In numbers dict.Add num, num Next ' Sort and display For Each key In dict.Keys WScript.Echo key Next This will output the numbers in ascending order.
addends
To find the median of an array of numbers, first, arrange the numbers in ascending order. If the array has an odd number of elements, the median is the middle number. If the array has an even number of elements, the median is the average of the two middle numbers.
import java.util.Arrays; import java.util.Scanner; public class Answers { public static void main(String[] args) { //Creates a scanner object named console. Scanner console = new Scanner(System.in); //Variabels int [] numbers = new int [10]; double avg = 0.0; double median = 0.0; int max = numbers[0]; double count = 0.0; //User input. for (int i = 0; i < numbers.length; i++){ System.out.print("Number: "); numbers[i] = console.nextInt(); } //break System.out.println("==============="); //finds the average and max value. for (int i = 0; i < numbers.length; i++){ count += numbers[i]; avg = count / numbers.length; //average if (numbers[i] > max){ //finds the max value. max = numbers[i]; } } median = (numbers[4] + numbers[5])/2; //Median value //Display to user. System.out.println("Highest value found: " + max); //Show maximum value found in array System.out.printf("Median is: %.3f \n",median); //Show median System.out.printf("Average is: %.3f \n",avg); //Show average sortAsc(numbers); //Print out whole array ascending } //Method for sorting an Array ascending. public static void sortAsc(int [] array){ for (int i = 0; i < array.length; i++){ Arrays.sort(array); System.out.println(array[i]); } } } This should do everything you asked for, hope this helps!
To display sorted unsigned or signed numbers in EASy68K, you can implement a simple sorting algorithm, such as bubble sort or selection sort. First, store the numbers in an array, then iterate through the array to compare and swap elements based on the desired order (ascending or descending). Finally, use system calls to print the sorted numbers. Here's a basic outline of the code structure: ; Assume numbers are stored in an array ; Sorting logic goes here (bubble sort or selection sort) ; Print sorted numbers using appropriate EASy68K syscall Make sure to handle signed and unsigned comparisons correctly based on the type of the numbers you're sorting.
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
To arrange numbers in ascending order in QBASIC, you can use a simple sorting algorithm like bubble sort. First, store the numbers in an array. Then, repeatedly compare adjacent elements and swap them if they are in the wrong order until the entire array is sorted. Here's a basic example: DIM numbers(5) AS INTEGER ' (Assume numbers are already populated) FOR i = 0 TO 4 FOR j = 0 TO 4 - i - 1 IF numbers(j) > numbers(j + 1) THEN SWAP numbers(j), numbers(j + 1) END IF NEXT j NEXT i This will sort the array numbers in ascending order.