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How do you display 15 numbers in an ascending order using an array?
Sort the array then traverse the array, printing the element values as you go.
Accept 5 numbers in an array and display it?
Accept 5 numbers in an array and display it.
How do you create Write a program that takes 10 integers as input The program will place these integers into an array and display the following 1. List in ascending order 2. mean 3. median 4.max val?
import java.util.Arrays; import java.util.Scanner; public class Answers { public static void main(String[] args) { //Creates a scanner object named console. Scanner console = new Scanner(System.in); //Variabels int [] numbers = new int [10]; double avg = 0.0; double median = 0.0; int max = numbers[0]; double count = 0.0; //User input. for (int i = 0; i < numbers.length; i++){ System.out.print("Number: "); numbers[i] = console.nextInt(); } //break System.out.println("==============="); //finds the average and max value. for (int i = 0; i < numbers.length; i++){ count += numbers[i]; avg = count / numbers.length; //average if (numbers[i] > max){ //finds the max value. max = numbers[i]; } } median = (numbers[4] + numbers[5])/2; //Median value //Display to user. System.out.println("Highest value found: " + max); //Show maximum value found in array System.out.printf("Median is: %.3f \n",median); //Show median System.out.printf("Average is: %.3f \n",avg); //Show average sortAsc(numbers); //Print out whole array ascending } //Method for sorting an Array ascending. public static void sortAsc(int [] array){ for (int i = 0; i < array.length; i++){ Arrays.sort(array); System.out.println(array[i]); } } } This should do everything you asked for, hope this helps!
Program to print all the even numbers of an array in visual basic?
find even number in array
Sort array in ascending descending order in python?
Using sorted(array,reverse=True)
How do you display 15 numbers in an ascending order using an array?
Sort the array then traverse the array, printing the element values as you go.
How can you write a c program to display numbers in ascending order in array?
I know how to do this and you need to know how to do this. Why don't you do your best at writing this program and if it does not work then ask for help. You will not learn anything if I give you the answer.
What will be the program to arrange numbers stored in array in ascending order using pointers?
sorry
Write a program for which give number in ascending number?
the following program will display all numbers given in the array in ascending order #include<stdio.h> void main() { int i,h,p; int numbers[10]={5,8,3,2,6,7,9,4,1,10}; for(p=0;p<=8;p=p+1) { for(i=0;i<=8;i=i+1) { if(numbers[i]>numbers[i+1]) { a=numbers[i]; numbers[i]=numbers[i+1]; numbers[i+1]=a; } } } for(i=0;i<=9;i=i+1) { printf("%d ",numbers[i]); } }
Accept 5 numbers in an array and display it?
Accept 5 numbers in an array and display it.
How do you arrange 4 numbers in ascending order without array?
addends
What is the process to find the median of an array of numbers?
To find the median of an array of numbers, first, arrange the numbers in ascending order. If the array has an odd number of elements, the median is the middle number. If the array has an even number of elements, the median is the average of the two middle numbers.
How do you create Write a program that takes 10 integers as input The program will place these integers into an array and display the following 1. List in ascending order 2. mean 3. median 4.max val?
import java.util.Arrays; import java.util.Scanner; public class Answers { public static void main(String[] args) { //Creates a scanner object named console. Scanner console = new Scanner(System.in); //Variabels int [] numbers = new int [10]; double avg = 0.0; double median = 0.0; int max = numbers[0]; double count = 0.0; //User input. for (int i = 0; i < numbers.length; i++){ System.out.print("Number: "); numbers[i] = console.nextInt(); } //break System.out.println("==============="); //finds the average and max value. for (int i = 0; i < numbers.length; i++){ count += numbers[i]; avg = count / numbers.length; //average if (numbers[i] > max){ //finds the max value. max = numbers[i]; } } median = (numbers[4] + numbers[5])/2; //Median value //Display to user. System.out.println("Highest value found: " + max); //Show maximum value found in array System.out.printf("Median is: %.3f \n",median); //Show median System.out.printf("Average is: %.3f \n",avg); //Show average sortAsc(numbers); //Print out whole array ascending } //Method for sorting an Array ascending. public static void sortAsc(int [] array){ for (int i = 0; i < array.length; i++){ Arrays.sort(array); System.out.println(array[i]); } } } This should do everything you asked for, hope this helps!
Program to count the number of numbers in an array using 8085 microprocessor?
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
What is the most efficient way to find the median of an unsorted array of numbers?
One efficient way to find the median of an unsorted array of numbers is to first sort the array in either ascending or descending order, then determine the middle value as the median.
PHP program to find the minimum number among a list?
Program to print all the even numbers of an array in visual basic?
find even number in array
