The choke works in conjunction with a starter . When you turn on the light , voltage is applied to the choke, and when the switch opens after a few seconds, it creates a high voltage across the contacts at each end of the tube. This starts the ionization of the gas , which glows. Once ionized, it continues producing light even when the voltage applied is only 120 VAC, the power line voltage.
No it will not. If you need increase the supply voltage and remove the choke.
If one light bulb in a series circuit fails, all the other light bulbs will go out, until the failed bulb is replaced and the series circuit is completed again.If one light bulb in a parallel circuit fails, all the other light bulbs will still work.
All of the light bulbs in the series circuit would go out.
It is very beneficial to have a parallel circuit... for example: 1. If one light in a parallel circuit goes out, the other light bulbs will remain lit Whereas if a light in a series circuit goes out, all bulbs will go out 2. If not all light bulbs are needed on, you can turn them off with the remaining light bulbs staying on
To make any electrical circuit work it has to be complete. Source of power to the load, the load itself and a return path from the load back to the source. The source in this case being the distribution panel. Any breaks in this complete path will cause the current to stop flowing and the device to not work. A light fixture and light switch work on this principle, open the circuit and the light goes out.
The choke works as an inductor(filter) induced 850V to 1100V in starting,by strarter make and break of the circuit. After glowing the tube light choke work as inductance and provide 110v to circuit, here the function of starter comes. It helps the chocke to brek from the circuit and to 110v from 850V.thankining U "Nikki"
No it will not. If you need increase the supply voltage and remove the choke.
Same choke tube as a 1200 or 1400 pump
A T8 LED tube has to be used with a ballast to bring the correct voltage to the tube for it to operate correctly. Removing the ballast from the circuit will prevent the tube from operating.
signal light
Tail light doesn't. Work with new bulb in
A 4-tube fluorescent light contains four fluorescent tubes connected to a ballast that regulates the electrical current flowing through the tubes. When the light switch is turned on, the ballast sends high voltage to the tubes to ionize the gas inside. This ionization process produces ultraviolet light, which then interacts with the phosphor coating inside each tube to produce visible light.
Once started the fluorescent tube no longer needs the starter. In fact starters are designed to electrically "remove" themselves from the circuit when the fluorescent tube is conducting.
If one light bulb in a series circuit fails, all the other light bulbs will go out, until the failed bulb is replaced and the series circuit is completed again.If one light bulb in a parallel circuit fails, all the other light bulbs will still work.
The work in an electric circuit is done by the flow of electric charge, typically achieved by the movement of electrons through a conductor. Work is done when a voltage is applied to the circuit, causing the electrons to move and transfer energy to the components in the circuit like light bulbs or motors.
In a series circuit, when a light bulb is broken, it creates an open circuit which stops the flow of current throughout the circuit. As a result, all the other light bulbs in the circuit will also stop working because they are all connected in a series.
Basically, when you click that switch, it completes a circuit for the electricity to flow. If the circuit is not completed in any part, the circuit will not work at all