Any constructor that can be invoked without explicitly passing any arguments is a default constructor. Note that there can be only one default constructor so there can only be one constructor where all arguments have default values or one constructor that has no arguments, but not both. A constructor where all arguments have default values is a useful means of combining two or more constructors into a single default constructor, thus reducing verbosity and code duplication.
The default constructor is an empty (only call the super constructor) with no parameters constructor inserted by the java compiler when you don't define a constructor in your class. If you write something like this: public class NoConstructorClass{ //no constructor goes here } Then you get something like this: public class NoConstructorClass{ public NoConstructorClass(){ // Default constructor that you didn't write super(); } }
Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments. Because there's no code in the no-arg version, it's actually identical to the default constructor the compiler supplies, but remember-since there's already a constructor in this class (the one that takes a string), the compiler won't supply a default constructor. If you want a no-arg constructor to overload the with-args version you already have, you're going to have to type it yourself, just as in the Car example. Overloading a constructor is typically used to provide alternate ways for clients to instantiate objects of your class. For example, if a client knows the Car name, they can pass that to a Car constructor that takes a string. But if they don't know the name, the client can call the no-arg constructor and that constructor can supply a default name
Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments. Because there's no code in the no-arg version, it's actually identical to the default constructor the compiler supplies, but remember-since there's already a constructor in this class (the one that takes a string), the compiler won't supply a default constructor. If you want a no-arg constructor to overload the with-args version you already have, you're going to have to type it yourself, just as in the Car example. Overloading a constructor is typically used to provide alternate ways for clients to instantiate objects of your class. For example, if a client knows the Car name, they can pass that to a Car constructor that takes a string. But if they don't know the name, the client can call the no-arg constructor and that constructor can supply a default name.
A constructor should be overloaded when there is a parameter with default value that is commonly used, or if it is possible that not all the information for creating the instance will be gathered all at once. As an example, say there is a class that describes bank accounts. Assuming I can choose to deposit or not deposit money under my name upon creating an account, there is a chance for a meaningful overload. One constructor could take in the name of the account owner and the initial balance as parameters; the overloaded constructor could just take the name as a parameter while setting the initial balance to zero.
Constructors have the same name as the class itself and they do not specify a return type, not even void because they return the instance of the class itself. Because constructors have the same name as the class then they allow method overloading and also save memory and execution time of program. Program release memory of constructors function after using this function and it reduce program complexity.
The default constructor is an empty (only call the super constructor) with no parameters constructor inserted by the java compiler when you don't define a constructor in your class. If you write something like this: public class NoConstructorClass{ //no constructor goes here } Then you get something like this: public class NoConstructorClass{ public NoConstructorClass(){ // Default constructor that you didn't write super(); } }
Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments. Because there's no code in the no-arg version, it's actually identical to the default constructor the compiler supplies, but remember-since there's already a constructor in this class (the one that takes a string), the compiler won't supply a default constructor. If you want a no-arg constructor to overload the with-args version you already have, you're going to have to type it yourself, just as in the Car example. Overloading a constructor is typically used to provide alternate ways for clients to instantiate objects of your class. For example, if a client knows the Car name, they can pass that to a Car constructor that takes a string. But if they don't know the name, the client can call the no-arg constructor and that constructor can supply a default name
Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments. Because there's no code in the no-arg version, it's actually identical to the default constructor the compiler supplies, but remember-since there's already a constructor in this class (the one that takes a string), the compiler won't supply a default constructor. If you want a no-arg constructor to overload the with-args version you already have, you're going to have to type it yourself, just as in the Car example. Overloading a constructor is typically used to provide alternate ways for clients to instantiate objects of your class. For example, if a client knows the Car name, they can pass that to a Car constructor that takes a string. But if they don't know the name, the client can call the no-arg constructor and that constructor can supply a default name.
A programmer-supplied default constructor is one that you, the programmer, explicitly implements in a class definition. A system-supplied constructor is one that is generated for you automatically by the compiler and are known as compiler-generated constructors for that reason.If you do not define any constructors, the compiler will automatically generate 3 constructors for you:a default constructora copy constructora move constructorThe default constructor is a constructor that requires no arguments. The compiler-generated default constructor invokes the default constructor for each data member but primitive data type members do not have constructors and are therefore left in an uninitialised state unless we use inline initialisation.The copy constructor accepts a constant l-value reference to an existing object of the same type. Data members are initialised using member-wise copy semantics. Uninitialised data members remain uninitialised in both objects.The move constructor accepts a non-constant r-value reference to an existing object of the same type. Individual data members are initialised using move semantics where available, otherwise copy semantics are used (as per the copy constructor).If you define any constructor, the compiler will not generate a default constructor unless you define your own. The compiler-generated copy and move constructors are always generated unless you provide your own implementation for one or both.It is considered good practice to explicitly declare all three constructors in order to make it clear to the class maintainer whether constructors are compiler-generated, user-defined, or deleted. For example:class A {public:A ()=default;A (const A&)=delete;A (A&&);// ...};A::A (A&&) {// ...}In the above example, the default constructor is compiler-generated (=default), the copy constructor is disabled (=delete) and the move constructor is user-defined.In most cases, the compiler-generated constructors will suffice, but if you need to provide a non-default constructor it's easy to forget that the default constructor will not be generated. Therefore get into the habit of being explicit. In the majority of cases, your class declarations will take the following form:class A { public:A ()=default;A (const A&)=default;A (A&&)=default;// ...};If you genuinely do not need a default constructor then declare it with the =delete postscript and provide your own non-default constructor (all classes must have at least one constructor that is neither a copy or a move constructor). Note that a user-defined constructor that takes one or more arguments where every argument has a default value is also a default constructor.In addition to copy and move constructors, the compiler also generates corresponding copy and move assignment operators as well as a destructor. Treat all compiler-generated code as a unified set; in most cases your classes will have the following form:class A {public:A ()=default;~A ()=default;A (const A&)=default;A& operator= (const A&)=default;A (A&&)=default;A& operator= (A&&)=default;// ...};There will be cases where the compiler-generated behaviour is undesirable. For instance, if your class acquires a resource, you will want to override all compiler-generated code with your own implementations in order to manage that resource. However, if you use smart pointers or resource handles rather than "naked" pointers, the compiler-generated behaviour provides exactly the semantic you want. The only time you really need to override that behaviour is when defining your own resource handles or smart pointers.Another reason to override the default construction behaviour is when you need to perform additional tasks that are not provided by the default semantics, such as when testing a class invariant. The copy/move constructors and assignment operators never need to test an invariant so the default semantic usually suffices, but all other constructors, assignment operators and other mutators (setters) must. Ideally, every class should have one and only one invariant at most. A string class, for instance, has an invariant in that it must always refer to a null-terminated string, even when the string is empty. By delegating that invariant to the string class itself, other classes can embed string objects without having to worry about the string invariant, they need only worry about their own invariant (if any).
Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples:class Car {Car() { }Car(String s) { }}The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments. Because there's no code in the no-arg version, it's actually identical to the default constructor the compiler supplies, but remember-since there's already a constructor in this class (the one that takes a string), the compiler won't supply a default constructor. If you want a no-arg constructor to overload the with-args version you already have, you're going to have to type it yourself, just as in the Car example.Overloading a constructor is typically used to provide alternate ways for clients to instantiate objects of your class. For example, if a client knows the Car name, they can pass that to a Car constructor that takes a string. But if they don't know the name, the client can call the no-arg constructor and that constructor can supply a default name. Here's what it looks like:1. public class Car {2. String name;3. Car(String name) {4. this.name = name;5. }6.7. Car() {8. this(makeRandomName());9. }10.11. static String makeRandomName() {12. int x = (int) (Math.random() * 5);13. String name = new String[] {"Ferrari", "Lamborghini","Rover", "Spyker","Lotus"}[x];14. return name;15. }16.17. public static void main (String [] args) {18. Car a = new Car();19. System.out.println(a.name);20. Car b = new Car("Proton");21. System.out.println(b.name);22. }23. }Running the code four times produces this output:% java CarLotusProton% java CarFerrariProton% java CarRoverProton% java CarFerrariProton
A constructor should be overloaded when there is a parameter with default value that is commonly used, or if it is possible that not all the information for creating the instance will be gathered all at once. As an example, say there is a class that describes bank accounts. Assuming I can choose to deposit or not deposit money under my name upon creating an account, there is a chance for a meaningful overload. One constructor could take in the name of the account owner and the initial balance as parameters; the overloaded constructor could just take the name as a parameter while setting the initial balance to zero.
Constructors have the same name as the class itself and they do not specify a return type, not even void because they return the instance of the class itself. Because constructors have the same name as the class then they allow method overloading and also save memory and execution time of program. Program release memory of constructors function after using this function and it reduce program complexity.
Having a mortgage in default can lead to serious consequences such as foreclosure, damage to credit score, loss of the property, and legal action by the lender.
no
There are no real, good arguments against planning. Having a plan is important in many cases.
A class can have any number of constructors, as far as they are having different parameters or different number of parameters. For example, a class A can have following constructors & even more: A() -the default constructor A(A objectA) -the copy constructor A(int p) A(int p1, int p2) A(int[] p1, float p2) A(double p1, double p2, int p3) A(A objA, int[] p) A(B objB)
Because if it's not by reference, it's by value. To do that you make a copy, and to do that you call the copy constructor. But to do that, we need to make a new value, so we call the copy constructor, and so on... (You would have infinite recursion because "to make a copy, you need to make a copy".)