45 in binary is 101101, so you need at least 6 bits to represent 45 characters.
23 can be represented in binary as 10111 and would therefore require 5 bits to represent.
It depends how many bits are used to represent each character and that ultimately depends on the machine architecture. If the machine can address memory in 8-bit bytes and each character is one byte in length, then "you are a students" would occupy at least 19 bytes including a null-terminator, which is 152 bits in total. However, you might wish to use proper English in your sentences. "You are a student." (152 bits) or "You are all students." (168 bits) would be preferred to the grammatically incorrect "you are a students". Sentences begin with a capital and end with a period, but we do not mix an indefinite article with a plural.
4.1 bit for 2,2 bits for 4,3 bits for 8,4 bits for 16.
17 bits would allow a value up to 131071.
10 bits would be required. 10 bits long (10 digits long) can represent up to 1024.
To represent 64 characters, you would need 6 bits. This is because 2^6 equals 64, meaning six bits can encode 64 different values, sufficient for each character. Each bit can represent two states (0 or 1), and with six bits, you can create combinations to represent all 64 characters.
bites
8 bits if unsigned, 9 bits if signed
To determine the minimum number of bits needed to store 100 letters and symbols, we first need to consider the total number of unique characters. Assuming we use the standard ASCII set, which includes 128 characters (letters, digits, and symbols), we can represent each character with 7 bits. Therefore, to store 100 characters, we would need a minimum of 700 bits (100 characters × 7 bits per character). However, if a larger character set like UTF-8 is used, it may require more bits for some characters.
A Byte is a collection of eight bits that can represent a single character.
4
how many bits are needed to represent decimal values ranging from 0 to 12,500?
The number of bits needed to represent one symbol depends on the total number of unique symbols. The formula to calculate the number of bits required is ( n = \lceil \log_2(S) \rceil ), where ( S ) is the number of unique symbols. For example, to represent 256 unique symbols, 8 bits are needed, since ( \log_2(256) = 8 ).
To represent a single EBCDIC character, typically 8 bits are required. However, to ensure error detection and correction, additional parity bits known as Hamming bits are added. In the case of a single EBCDIC character, typically 4 Hamming bits are added, resulting in a total of 12 bits to represent the character. These Hamming bits help detect and correct errors that may occur during transmission or storage of the data.
"recommended setting" There are 19 characters including the space between the two words. If the old convention of using 1 byte to represent a character, then we would need (19 x 8) which is 152 bits. If we use unicode as most modern computers use (to accommodate all the languages in the world) then 2 bytes will represent each character and so the number of bits would be 304.
A nibble (also known as a nybble or nyble) can represent half a character(two nibbles are needed for a valid ASCII character). A nibble is made up of 4 bits and those 4 bits are usually represented by a single hexadecimal value. 4 bits only allows for 16 combinations, 8 bits allows for 255. An ASCII character is represented by two hexadecimal characters, which is the same as 8 bits or two nibbles.
A standard deck of playing cards has 52 cards. To determine how many bits are needed to represent each card, we can use the formula ( \lceil \log_2(52) \rceil ). Since ( \log_2(52) ) is approximately 5.7, we round up to 6 bits. Therefore, 6 bits are needed to uniquely represent each card in a standard deck.