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To determine how many grams of ethylene (C₂H₄) must burn to release 70.0 kg of heat, we first need the heat of combustion of C₂H₄, which is approximately 1410 kJ/mol. Converting 70.0 kg of heat to kJ gives 70,000 kJ. Using the heat of combustion, we can calculate the moles of C₂H₄ needed: 70,000 kJ ÷ 1410 kJ/mol ≈ 49.6 mol. Finally, multiplying by the molar mass of C₂H₄ (about 28.05 g/mol) gives approximately 1390 grams of C₂H₄ required.

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2mo ago

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