To determine how many grams of ethylene (C₂H₄) must burn to release 70.0 kg of heat, we first need the heat of combustion of C₂H₄, which is approximately 1410 kJ/mol. Converting 70.0 kg of heat to kJ gives 70,000 kJ. Using the heat of combustion, we can calculate the moles of C₂H₄ needed: 70,000 kJ ÷ 1410 kJ/mol ≈ 49.6 mol. Finally, multiplying by the molar mass of C₂H₄ (about 28.05 g/mol) gives approximately 1390 grams of C₂H₄ required.
£7000000000000000 per gram
1 newton= gram ? 1 newton=kilogram?
he invented the tin wrapped foil that was able to be played on the phonograph and in 1973
It is a very good question. I am pretty sure it is about 10 grams. This is possible because one millimeter is the same as one gram. Hence I figured that since one centimeter in ten millimeters I thought that you should times it by ten. So the answer should be ten.
The top of a CO2 canister isn't very thick. It will take about a half a pound of pressure to break through the top.
A person would have to burn about four calories to equate one gram of protein. Carbohydrates also contain four calories per gram, while fat contains nine.
Greater latent heat in steam due to phase change.
A gram of any kind of fat is about 8 calories. The time to burn it depends on your activity. You burn calories even at rest (1.6 calories/hour) so at rest it would take you about 5 hours to burn 1 gram of fat. If instead of sitting alone in a chair you were kissing someone you would burn 8 calories in about 5 minutes. If you were walking you would burn 8 calories in 2 or 3 minutes.
True. It takes four calories to burn one gram of carbohydrate.
give me tracking number in money gram
Carbohydrates like sugar contain 4 kcal/gram. So, 22g of sugar contains 22x4=88 kcal. Walking a mile should burn this amount.
Some things are non flammable. Calories are released not used during burning. For the above two reasons your question makes no sense.
1 gram of pure para-acetaminophenol
9 calories are the equivalent to 1 gram of fat.
The gram molecular mass of C2H4 is 28.05. Therefore, 1.26 X 103 grams constitutes (1.26/28.05) X 103 or about 44.9 moles. Each mole contains Avogadro's number of molecules; therefore, 1.26 X 103 grams contains 2.71 X 1025 molecules, to the justified number of significant digits.
lll.ogn.org
Typical gram-positive bacteria are staphylococci; typical gram-negative bacteria are bacilli.