A standard NOT gate will have just one input. It will change its value to the opposite digital value for the output.
ans. 3 nand gates resoon :- OR GATE :- x+y NAND GATE :- x'+y' LOGIC :-so the logic is is we apply NAND to the inputs x' and y' instead of xand y we would get x+y DESIGN PROCEDURE 1. for inverting the input x and y can be done by NAND gates , 2. take a NAND gate and pass both x in both the inputs it means x NAND x gives you x' 3. follow similar procedure for inverting y 4. and then all the outputs of those NAND gates as the inputs of another NAND gate
An AND gate
The XOR (exclusive OR) gate detects if the inputs are different. It outputs a high signal (1) when the inputs are not the same (one input is high and the other is low) and outputs a low signal (0) when the inputs are the same. Thus, it effectively identifies the difference between the two inputs.
Its a very versatile chip. It can be used in many places where logic control is required. As there are four identical NOR gates in one package, the inputs and outputs can be configured to make up quite complicated logic gates. Being a NOR gate, the the output will be at supply level, until one or both of the inputs are taken high. At which point the output will go low. The uses are many and varied. The 4000 series of chip are CMOS, so they can work at voltages between 5 and 12volts at low current.
A multiplexer, commonly referred as an input selector, is a circuit with many inputs but only one output: it has some data inputs, control inputs and one output, depending on the control inputs, one input from the data inputs is sent to the output .A demultiplexer is a circuit with one data input, few control inputs and many outputs, it is also known as output selector.
A: two
ans. 3 nand gates resoon :- OR GATE :- x+y NAND GATE :- x'+y' LOGIC :-so the logic is is we apply NAND to the inputs x' and y' instead of xand y we would get x+y DESIGN PROCEDURE 1. for inverting the input x and y can be done by NAND gates , 2. take a NAND gate and pass both x in both the inputs it means x NAND x gives you x' 3. follow similar procedure for inverting y 4. and then all the outputs of those NAND gates as the inputs of another NAND gate
An AND gate
A "Nand" gate is an "And" gate with an "Inverter" added to its output. To get a logic 1 output from a "Nand" gate, you need a logic 0 on both of its inputs. If I understand your question correctly, you have three "Nand" gates. Presumably the outputs of two of them are connected to the inputs of the third. Logic 1 at both inputs of the first two "Nand" gates will produce a logic 0 output from both of them. The two logic 0's are fed to the inputs of the third "Nand" gate producing a logic 0 output from the third "Nand" gate.
AND gate is A.B If two not gates are added at both inputs of and gate then output becomes A'.B' which is equal to (A+B)' by DeMorgan's law. hence the nor gate is formed Update: Put more simply, invert A and B by attaching A to both inputs of one NOR and attaching B to both inputs of another NOR, then NOR the results of the previous two NOR gates. Total of three NOR gates in a two-level implementation. NAND can obviously be created by inverting the result.
The XOR (exclusive OR) gate detects if the inputs are different. It outputs a high signal (1) when the inputs are not the same (one input is high and the other is low) and outputs a low signal (0) when the inputs are the same. Thus, it effectively identifies the difference between the two inputs.
By using 5 NOR gates, we can implements half-subtractor. The inputs for 1st NOR gate are A and B, for 2nd NOR gate inputs are the output of 1st NOR gate and A input, for 3rd NOR gate inputs are the output of 1st NOR gate and B input, for 4th NOR gate the inputs are gates 2 and 3, and for last gate input is the output of the 4th gate.
It means that C is the inverse of A. Implementing the equation C = !A in basic logic gates requires the use of an inverter. An inverter can be made from a dedicated inverter gate, if available, or from a NAND gate with n inputs, where all n inputs are connected to A.
To produce a 3-input OR gate when only 2-input OR gates are available: Use 3 OR gates Inputs to Gate A are input 1 and input 2 Input to Gate B is input 3 (if 2 inputs are necessary, include input...
That package contains four 2-input NAND gates with Schmitt-trigger inputs.
combinational circuit is depend only on inputs,like sequential circuits its not depend on previous outputs.
3 inputs and 2 outputs