It would be the sum of the two resistances, as they are connected in series.
It depends on where the capacitor is located. If it is across the emitter resistor, then the gain of the CE amplifier will be higher at higher frequencies.Remember that gain in the CE amplifier is collector resistance divided by emitter resistance, or hFe, whichever is lower. Placing a capacitor across the emitter resistor will serve to make the effective resistance smaller at higher frequencies, resulting in increased gain, up to the limit of hFe.If this is not the intended location of the capacitor, then please restate the question and provide the capacitor location.
The battery is used by the meter to apply a voltage across the resistance being measured and determine the current which determines the resistance. If there is no battery it can't supply the voltage and can't measure current, so no reading.
ANY METER needs some kind of current flow to operate. Internal in the meter there are batteries that provide current that when passed trough a resistor will develop voltage as a function of the current. the meter will read this current and display the resistor size to cause this current to flow.
There are many ways. FIRST: short the terminals to ensure it is not charged. Many of the digital meters today also have a capacitance check setting, simply use that setting. It not only checks for faults, but also will give you a reading of the capacitance value itself. For most non-electrolytic capacitors a quick check (definately bad vs. maybe good) can be done with an analog VOM. Use the highest resistance scale to measure across the terminals. When first connected there should be a short needle jump that slowly drops back to infinity. Reverse the leads and do it again, should have the same effect. Any resistance highter than infinity indicates a shorted capacitor. Lack of needle jump may indicate an open capacitor (or one of very little capacitance). Electrolytics can also be checked with a VOM, but polarity must be observed, and the drop back to infinity may take a very long time. Alternatively, for electrolytics and larger capacitors is to charge them with a low voltage source (e.g. 9V battery) and measure with multimeter to see if they hold the charge.
An ohmmeter works by sending a small amount of electrical current through the component being tested and measuring the voltage drop across it. The ohmmeter then uses Ohm's Law (VIR) to calculate the resistance of the component based on the current and voltage readings.
It would be the sum of the two resistances, as they are connected in series.
It depends on where the capacitor is located. If it is across the emitter resistor, then the gain of the CE amplifier will be higher at higher frequencies.Remember that gain in the CE amplifier is collector resistance divided by emitter resistance, or hFe, whichever is lower. Placing a capacitor across the emitter resistor will serve to make the effective resistance smaller at higher frequencies, resulting in increased gain, up to the limit of hFe.If this is not the intended location of the capacitor, then please restate the question and provide the capacitor location.
It can be used as a feedback and to ground unwanted signals and frequencies
If a bypass capacitor is used the voltage drop across emitter resistance is reduced which in turn increases the gain.....
A capacitor discharges by releasing stored electrical energy. The rate of discharge is affected by factors such as the capacitance of the capacitor, the resistance of the circuit, and the voltage across the capacitor. A higher capacitance or lower resistance will result in a slower discharge rate, while a higher voltage will lead to a faster discharge.
Capacitive reactance is an opposition to changes in voltage across an element. This resistance is usually caused by a magnetic field.
An ohmmeter is a device used to measure the electrical resistance of a circuit component or material. It works by sending a known current through the component and measuring the voltage drop across it. The ohmmeter then uses Ohm's Law (V=IR) to calculate the resistance of the component in ohms. This measurement helps in troubleshooting electrical circuits, testing the integrity of components, and determining if there are any faults or breaks in the circuit.
No, the voltage across a capacitor cannot change instantaneously. It takes time for the voltage across a capacitor to change due to the storage and release of electrical energy in the capacitor.
The battery is used by the meter to apply a voltage across the resistance being measured and determine the current which determines the resistance. If there is no battery it can't supply the voltage and can't measure current, so no reading.
The easiest way is to use an Ohmmeter. This function is usually built into most multimeter that can be bought at any hardware store. An Ohmmeter measures the electrical resistance of a material. The lower the number the more conductive that material is. If the Ohm reading is above the maximum reading on the meter then their is infinite resistance which means that the material is not a conductor of electricity.
ANY METER needs some kind of current flow to operate. Internal in the meter there are batteries that provide current that when passed trough a resistor will develop voltage as a function of the current. the meter will read this current and display the resistor size to cause this current to flow.