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How to subtract the hexadecimal number 1245 from D257 using two's complement addition method?
You take 1245 and form the two's complement of it then add it to D257.
The two's complement of a number is defined as the 1's complement + 1. In signed two's complement arithmetic, the most significant bit is the "sign" bit. 1 indicates a negative number and 0 indicates a positive number. To find the magnitude of a negative number, take it's two's complement (ignoring carry bits).
To get the two's complement of 1245, take the 1's complement of 1245 and add 1. In binary 1245 is 0001001001000101. The one's complement is 1110110110111010 (in hex that's EDBA) . Adding 1 to this will give you the two's complement. That is EDBA+0001 (ignore the carry if any), is EDBB. Now you add EDBB to D257 and ignore any carry, so that will be 1C012 (throw away the carry bit), C012. C012 is a negative number (the sign bit, the most significant bit, is 1). To find its magnitude, apply the two's complement algorithm above, and you'll find it to be -16365.
Note: D257 is a negative number, and you're subracting a positive number, so you're going to end up with another negative number, i.e. adding the two's complement of a number is the same thing as subtracting the number.
You can check your result by doing the math in decimal to see if it adds up. D257 in decimal = -11688 (you apply the two's complement to the number to find the magnitude, and the sign is negative because the sign bit, the most signficant bit is 1). 1245 in decimal = 4677. -11688-4677 = -16365 (which in hex signed two's complement is C012).
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Subtract the hexadecimal number 1234 from DA57 using twos complement addition method?
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