How would you write a program to display even numbers between 0-20?

Answer 1

ALGORITHM EVEN

BEGIN

FOR ( num = 0; num <= 20; num++ )

BEGIN

IF ( num MOD 2 == 0 ) THEN

DISPLAY (num)

END IF

END FOR

END EVEN

in C:

#include <stdio.h>

int main (void) { puts ("0 2 4 6 8 10 12 14 16 18 20"); return 0; }

Answer 2

#include<iostream.h>

#include<stdlib.h>

int main( )

{

int i=1;

for( i = 1; i<20; i++)

{

if( i%2 == 1)

{

cout << "\n" << i ;

}

}

system("PAUSE");

return 0;

}

Answer 3

The following loops through the numbers, 2 at a time:

for (i = 2; i <= 200; i+=2)
System.out.print(i + " ");

Here is another version; loop through all the numbers, and check whether each number is even:

for (i = 1; i <= 200; i++)
if (i % 2 == 0) // Checks remainder of division by 2
System.out.print(i + " ");

Answer 4

public class even_no {

public static void main( String args[])

{

int x=2;

for(x=2;x<=100;x+=2)

{

System.out.println(x);

}

}

}

Answer 5

#include <iostream>

int main()

{

for(int i = 100; i >= 1; i--)

{

if(i % 2 != 0)

printf("%d\n", i);

}

return 0;

}

Answer 6

int i;

for (i=2; 2<=20; i+=2) printf ("%d\n", i);

Answer 7

No if...else is required; what condition do you need? Just use a loop. For example, in Java: for (int i = 1; i

Answer 8

Here are two options in Java: // Option 1, increment by 2 at a time: for (int i = 2; i

Answer 9

Notepad++