Use the random number generator classes.
#include<random>
#include<ctime>
std::default_random_engine generator ((unsigned)time(0)); // seed the generator
std::uniform_int_distribution<int> distribution (0, 100); // set the closed range
int r = distribution (generator); // pick a random number from 0 to 100 (inclusive)
Any device can be used to seed the generator. Here, we've simply used the current time. If you don't seed the generator, it will generate the same sequence of random values every time the program is run.
The rand() function returns an integer (int) value that represents a pseudo-random number between 0 and RAND_MAX, RAND_MAX being a constant declared in the run-time library. Each time rand() is invoked, a different value is returned.
Use sizeof( ).
You can't, you have to come up with variables to calculate grades
int die = ((double)rand())*6/RAND_MAX+1; // result is 1, 2, 3, 4, 5, or 6
#include<stdio.h> #include<stdlib.h> int main(void) { int i; int j[100]; for(i=0;i<100;i++) { j[i]=rand()%100; printf("%d",j[i]); } }
You can use rand(). Make sure that you use srand()to generate the seed for rand() (if you do not, you get so called pseudo random numbers).
The rand() function returns an integer (int) value that represents a pseudo-random number between 0 and RAND_MAX, RAND_MAX being a constant declared in the run-time library. Each time rand() is invoked, a different value is returned.
Use sizeof( ).
Marguerite C. Rand has written: 'Ramo n Pe rez de Ayala'
You can't, you have to come up with variables to calculate grades
Your question is not clear. Please give the formula to calculate the value of x and the condition at which the line cuts the circle
cn = c0 *( 1 + i ) pow n
Neill C. Ostrander has written: 'The Rand Sync-Sat Calculator' -- subject(s): Rand Sync-Sat Calculator, Syncom (Communications satellite)
int die = ((double)rand())*6/RAND_MAX+1; // result is 1, 2, 3, 4, 5, or 6
There are four unknown variables and only three linear equations so there is not a unique solution. All you can do is to rearrange the four variables so that three of them can be expressed in terms of the fourth. For example: In terms of c, a = 6 - c/2 b = a - c = 6 - 3c/2 d = c
b+b+b+c+c+c+c =3b+4c
c + c + 2c + c + c = 6c