To find the length of segment PN when you know the lengths of segments PQ and QN, you can use the relationship that PN is the sum of PQ and QN. Specifically, if PQ and QN are adjacent segments along a straight line, then PN = PQ + QN. If they are not aligned, you would need additional information about their orientation to determine PN accurately.
Qn =JQ'+K'Q
Here is qn excellent article that explains step by step: http://MasteringElectronicsDesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/
#include<stdio.h> #include<conio.h> #include<graphics.h> #include<stdlib.h> #define pf printf #define s scanf int gd=DETECT, gm, pa, o, b; int i; int x, y, i,ch,c; int c, m, p, qn, cm, mp, cp, cmp, n, k, p1, g,qcm,qmp,qcp,qc,qm,qp; void main() { initgraph(&gd,&gm," "); cleardevice(); line(0,0,639,0); line(0,0,0,479); line(639,0,639,479); line(639,479,0,479); line(589,479,0,479); randomize(); for(i=0;i<640;i++) { setcolor(i); x=rand()%639; y=rand()%480; putpixel (x,y,i); { setcolor(RED); settextstyle(3,0,5); outtextxy(60,100, "PROJECT IN DISCRETE"); setcolor(RED); settextstyle(3,0,5); outtextxy(80,135, "MATHEMATICS"); setcolor(i); settextstyle(2,0,5); outtextxy(120,192,"SUBMITTED BY :"); setcolor(i); settextstyle(2,0,5); outtextxy(120,202,"Cabrera"); setcolor(i); settextstyle(2,0,5); outtextxy(120,214,"Gaspar"); setcolor(i); settextstyle(2,0,5); outtextxy(120,226,"Molina"); setcolor(i); settextstyle(2,0,5); outtextxy(120,238,"Viray"); } setcolor(i); settextstyle(2,0,5); outtextxy(400,350,"U P L O A D i N G..."); setcolor(WHITE); outtextxy(i,378,"="); outtextxy(i,406,"="); setcolor(WHITE); circle(i,400,10); delay(1); } cleardevice(); gotoxy(10,7); pf("Enter 1 for V E N N D I A G R A M "); gotoxy(10,8); pf("Enter 2 for S E T N O T A T I O N"); gotoxy(10,10); printf("Input: "); s("%d",&pa); cleardevice(); { if(pa==1) { { line(0,0,639,0); line(0,0,0,479); line(639,0,639,479); line(639,479,0,479); line(589,479,0,479); randomize(); for(i=0;i<640;i++) { setcolor(i); x=rand()%639; y=rand()%480; putpixel (x,y,i); { setcolor(i); settextstyle(9,0,5); outtextxy(60,100, "V E N N"); setcolor(i); settextstyle(9,0,5); outtextxy(80,165, "D I A G R A M"); } setcolor(i); settextstyle(2,0,5); outtextxy(400,350,"U P L O A D i N G..."); setcolor(YELLOW); outtextxy(i,378,"="); outtextxy(i,406,"="); setcolor(WHITE); circle(i,400,10); delay(1); } sleep(1); cleardevice(); } gotoxy(10,7); pf("Enter 1 if the Outside is missing. 3 Circle. "); gotoxy(10,8); pf("Enter 2 if the Total is missing. 3 Circle."); gotoxy(10,11); printf("Choice : "); s("%d",&p1); for(g=1;g<=8;g++) { if(p1==1) { cleardevice(); gotoxy(32,8); pf("Input the Values for the following variables:"); gotoxy(32,11); pf("X:"); gotoxy(32,12); pf("Y:"); gotoxy(32,13); pf("Z:"); gotoxy(32,14); pf("XY:"); gotoxy(32,15); pf("XZ:"); gotoxy(32,16); pf("YZ:"); gotoxy(32,17); pf("XYZ:"); gotoxy(32,18); pf("Outside:"); gotoxy(32,19); pf("Total Number:"); { if(g==1){gotoxy(42,18);pf("----");gotoxy(42,11);s("%d",&c);} if(g==2){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);s("%d",&m);} if(g==3){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);s("%d",&p);} if(g==4){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);scanf("%d",&cm);} if(g==5){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);s("%d",&cp);} if(g==6){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);s("%d",&mp);} if(g==7){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);pf("%d",mp);gotoxy(42,17);s("%d",&cmp);} if(g==8){gotoxy(42,18);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);pf("%d",mp);gotoxy(42,17);pf("%d",cmp);gotoxy(50,19);s("%d",&k);} cleardevice(); }} { qcm=cm-cmp; qmp=mp-cmp; qcp=cp-cmp; qc=c-(qcp+cmp+qcm); qm=m-(qcm+cmp+qmp); qp=p-(qcp+cmp+qmp); qn=k-(cmp+qcp+qcm+qmp+qc+qm+qp); } cleardevice(); setcolor(RED); rectangle(600,450,40,40); setcolor(YELLOW); circle(250,200,125); setcolor(GREEN); circle(375,200,125); setcolor(BLUE); circle(313,300,125); gotoxy(39,15); printf("%d",cmp); gotoxy(30,4); printf("X"); gotoxy(49,4); printf("Y"); gotoxy(23,12); printf("%d",qc); gotoxy(55,12); printf("%d",qm); gotoxy(39,23); printf("%d",qp); gotoxy(39,9); printf("%d",qcm); gotoxy(30,18); printf("%d",qcp); gotoxy(49,18); printf("%d",qmp); gotoxy(63,25); printf("%d",qn); gotoxy(39,27); setcolor(WHITE); outtextxy(310,435,"Z"); } for(g=1;g<=8;g++) { if(p1==2) {cleardevice(); gotoxy(32,8); pf("Input the Values for the following variables:"); gotoxy(32,11); pf("X:"); gotoxy(32,12); pf("Y:"); gotoxy(32,13); pf("Z:"); gotoxy(32,14); pf("XY:"); gotoxy(32,15); pf("XZ:"); gotoxy(32,16); pf("YZ:"); gotoxy(32,17); pf("XYZ:"); gotoxy(32,18); pf("Outside:"); gotoxy(32,19); pf("Total Number:"); { if(g==1){gotoxy(42,19);pf("----");gotoxy(42,11);s("%d",&c);} if(g==2){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);s("%d",&m);} if(g==3){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);s("%d",&p);} if(g==4){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);scanf("%d",&cm);} if(g==5){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);s("%d",&cp);} if(g==6){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);s("%d",&mp);} if(g==7){gotoxy(42,19);pf("----");gotoxy(42,11);pf("%d",c);gotoxy(42,12);pf("%d",m);gotoxy(42,13);pf("%d",p);gotoxy(42,14);pf("%d",cm);gotoxy(42,15);pf("%d",cp);gotoxy(42,16);pf("%d",mp);gotoxy(42,17);pf("%d",cmp);gotoxy(42,18);s("%d",&n);} cleardevice(); }} { qcm=cm-cmp; qmp=mp-cmp; qcp=cp-cmp; qc=c-(qcp+cmp+qcm); qm=m-(qcm+cmp+qmp); qp=p-(qcp+cmp+qmp); qn=k-(cmp+qcp+qcm+qmp+qc+qm+qp); } cleardevice(); setcolor(RED); rectangle(600,450,40,40); setcolor(YELLOW); circle(250,200,125); setcolor(GREEN); circle(375,200,125); setcolor(BLUE); circle(313,300,125); gotoxy(39,15); printf("%d",cmp); gotoxy(30,4); printf("X"); gotoxy(49,4); printf("Y"); gotoxy(23,12); printf("%d",qc); gotoxy(55,12); printf("%d",qm); gotoxy(39,23); printf("%d",qp); gotoxy(39,9); printf("%d",qcm); gotoxy(30,18); printf("%d",qcp); gotoxy(49,18); printf("%d",qmp); gotoxy(63,25); printf("%d",qn); gotoxy(39,27); setcolor(WHITE); outtextxy(310,435,"Z"); } } getche(); } { if(pa==2) { { line(0,0,639,0); line(0,0,0,479); line(639,0,639,479); line(639,479,0,479); line(589,479,0,479); randomize(); for(i=0;i<640;i++) { setcolor(i); x=rand()%639; y=rand()%480; putpixel (x,y,i); { setcolor(i); settextstyle(9,0,5); outtextxy(60,100, "S E T"); setcolor(i); settextstyle(9,0,5); outtextxy(50,165, "N O T A T I O N"); } setcolor(i); settextstyle(2,0,5); outtextxy(400,350,"U P L O A D i N G..."); setcolor(YELLOW); outtextxy(i,378,"="); outtextxy(i,406,"="); setcolor(WHITE); circle(i,400,10); delay(1); } sleep(1); cleardevice(); } printf("ogi"); getche(); } } cleardevice(); gotoxy(10,10); printf("--END--"); getche(); }
No. First, the answer depends on how distance is defined. There are many ways of defining metrics. With the common definition "Euclidean distance", in 2 or more dimensions, the distance between P and Q is calculated using the generalised form of Pythagoras's theorem. Thus, if P = (p1, p2, ..., pn) and Q = (q1, q2, ... , qn) are the coordinates of points P and Q in n-dimensional space, then the distance PQ is qiven by |PQ|2 = (p1 - q1)2 + (p2 - q2)2 + ... + (pn - qn)2 and so |PQ| is the principal square root of the above. In 1-dimensional space (along a line), this simplifies to |PQ|2 = (p1 - q1)2 so that |PQ| = |p1 - q1| and this will always be less than or equal to abs(p and q).
Let's say Un=aqn and Sn=a+aq+aq2+aq3+aq4+aq5+...+aqn Sn = a (1+q+q2+q3+q4+q5+...+qn) A=(Sn/a) - q (Sn/a) = (1+q+q2+q3+q4+q5+...+qn) - q(1+q+q2+q3+q4+q5+...+qn) A=1+q+q2+q3+q4+q5+...+qn-q-q2-q3-....-qn-qn+1=1-qn+1 So A = 1-qn+1 = Sn/a (1-q) So Sn = a (1-qn+1)/(1-q)
There are no nouns in the English language that begin with the letters qn.
what is immunoglobulin for
yellow, according to http://www.ussoccer.com/News/Womens-National-Team/2010/03/USA-Defeats-Mexico-in-First-Ever-Snow-Game-For-WNT.aspx the other answers to the jabulani quiz; qn 2. - 7 qn 3; - humberto suazo qn 4; - 35 matches qn 5; - 1962
QN+1=T exor QN
This is not a stupid Qn. The gentle man who asked this Qn is genious. The average cost of a commercial building is the funds which is in your hands.
sq, hq, aq, eq, cq, dq, iq, pq, qq, gq, kq, nq, rq, xq, qn, qb, qr, qs, qu, qe, qp, ql, qm, qq, qt, qv, qy, qa, qc, qd, qf, qh
4 months
Yes. An Octopus has no internal skeleton.
i dont' know, i have the same qn too
Qn =JQ'+K'Q