0
NO
some armored cable has a ground
some sealtite has copper in the helix wit the drain shield
some liquite has no conduction at all
all armor is a helix which is a coil and acts as insulation at hi frequency
xlpe cross linked polyethylene is an insulator
service cable is never used for grounding
grounding electrode conductor
grounding equipment conductor
grounding conductor
are all separate from service cables
if a tall trucks hits an overhead cable you dont want to lose the ground
in short
NO
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What county is zip code 60502 in?
Aurora, Illinois
Tickets are 18 in advance or 34 if purchased on the day of the game at half time it is announced that 2155 tickets were sold the revenues are 60502 how many tickets were sold?
798 advance tickets and 1357 regular tickets were sold. Say x is the number of advance tickets and y is the number of regular tickets. So x + y = 2155 since 2155 is the number of tickets sold with x and y . We also know that 18x +34y = 60502 since x the advance tickets are $18 and y the regular tickets are $34 and the total proceeds are $60502. Alright now we can solve for either x or y. Let's solve for y. How do we do that? We get rid of x from the formula. So look at this. 18x = 60502 - 34y (just a modification of the second formula), x = 2155 - y (just a modification of the first formula) and then multiply that whole thing by 18 so 18x= 18(2155) - 18y which is 18x = 38790 - 18y. So we know 18x = 60502 - 34y and 18x = 38790 -18y so since 18x = 18x, 60502 - 34y = 38790 - 18y. Now we want the y all on the same side so let's add 34y to both sides and you get 60502 = 38790 + 16y. Then subtract 38790 from both sides and you get 60502 - 38790 = 16y which is 21712 = 16y which divided by 16 is 1357 = y. That's your number of regular tickets. Now then x + y = 2155 or x = 2155 - y so x = 2155 - 1357 = 798. So x is 798 and y is 1357. You can even plug it back into the problem and it works. 18x + 34y = 60502 which is 14364 + 46138 = 60502 and thankfully 14364 + 46138 does equal 60502.
What is the area of a football field in meters?
An American football field is 109.7 m by 48.8 m.
