Math is the class, and sqrt() is the method.
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3.4086580994024981055126631335409sqrt(3)= 1.7320508075688772935274463415059sqrt(15) = 3.8729833462074168851792653997824sqrt(3) x sqrt(15) = 6.7082039324993690892275210061938 = sqrt(45) = 3 x sqrt(5)AnswerThis is an example of a question that's ambiguous because it hasn't been written mathematically. The above answer is for sqrt(3) x sqrt(15). Another interpretation of the question would be sqrt(3 x sqrt(15)), which has a different answer.
Vtop = sqrt(2)*Veffective so Veffective = Vtop / sqrt(2)
No commands in C; the name of function sqrt is sqrt (include math.h; and use -lm at linkage)
square root of the argument
Approximately 2.828427
sqrt 8 = sqrt 4 x 2 = 2 sqrt 2 But you wouldn't use "sqrt" to replace the proper math sign
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is the number 7 in real math a whole number
Well, isn't that just a happy little question! The square root of 38 is actually an irrational number because it cannot be expressed as a simple fraction. It's like a beautiful little mystery in the world of numbers, just waiting to be explored and appreciated. Just remember, there's no mistakes in math, only happy little accidents!
It is a Kangxi radical. The best way to display this radical is: sqrt(11)*sqrt(5)*sqrt(3). To get more information on these kinds of radicals one could visit websites such as Cool Math.
Oh, dude, imaginary numbers? Like, sure, let's do this. So, the square root of negative 48 can be simplified as 4iā3. It's like regular math, but with a little twist of imagination. So, there you have it, imaginary math for the win!
Expressed as a surd in its simplest form, sqrt(7.2) = 6 sqrt(5)/5 Expressed as a decimal, rounded to two decimal places, sqrt(7.2) = ±2.68
sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).
sqrt(1^2 + 1^2 ) = sqrt(2)sqrt(sqrt(2)^2 + 1^2 ) = sqrt(3)sqrt(sqrt(3)^2 + 1^2 ) = sqrt(4)sqrt(sqrt(4)^2 + 1^2 ) = sqrt(5)sqrt(sqrt(5)^2 + 1^2 ) = sqrt(6)sqrt(sqrt(6)^2 + 1^2 ) = sqrt(7)sqrt(sqrt(7)^2 + 1^2 ) = sqrt(8)sqrt(sqrt(8)^2 + 1^2 ) = sqrt(9)sqrt(sqrt(9)^2 + 1^2 ) = sqrt(10)sqrt(sqrt(10)^2 + 1^2 ) = sqrt(11)sqrt(sqrt(11)^2 + 1^2 ) = sqrt(12)sqrt(sqrt(12)^2 + 1^2 ) = sqrt(13)sqrt(sqrt(13)^2 + 1^2 ) = sqrt(14)sqrt(sqrt(14)^2 + 1^2 ) = sqrt(15)sqrt(sqrt(15)^2 + 1^2 ) = sqrt(16)sqrt(sqrt(16)^2 + 1^2 ) = sqrt(17)
sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).
The question is ambiguous because it could refer to [sqrt(A2B) + sqrt(AB2)]/sqrt(AB) = [A*sqrt(B) + B*sqrt(A)]/[sqrt(A)*sqrt(B)] = A/sqrt(A) + B/sqrt(B) = sqrt(A) + sqrt(B) or sqrt(A2B) + sqrt(AB2)/sqrt(AB) = A*sqrt(B) + B*sqrt(A)/[sqrt(A)*sqrt(B)] = A*sqrt(B) + B/sqrt(B) = A*sqrt(B) + sqrt(B) = sqrt(B)*(1 + A)