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Math is the class, and sqrt() is the method.

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Q: In a java statement Math.sqrt what is Math and what is sqrt?
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Related questions

What is sqrt 2 plus sqrt 2?

Approximately 2.828427


How do you simplify the square root of 8?

sqrt 8 = sqrt 4 x 2 = 2 sqrt 2 But you wouldn't use "sqrt" to replace the proper math sign


How do you square root in java?

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Is the sqrt 7 a whole number?

is the number 7 in real math a whole number


What is the radical of the figure 165?

It is a Kangxi radical. The best way to display this radical is: sqrt(11)*sqrt(5)*sqrt(3). To get more information on these kinds of radicals one could visit websites such as Cool Math.


What is the square root of 7.2?

Expressed as a surd in its simplest form, sqrt(7.2) = 6 sqrt(5)/5 Expressed as a decimal, rounded to two decimal places, sqrt(7.2) = ±2.68


Is the square root of 38 rational or irrational?

\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}\sqrt{38}


What is the square root of 72 using radicals?

sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).


What are the first 16 equations for the wheel of theodorus?

sqrt(1^2 + 1^2 ) = sqrt(2)sqrt(sqrt(2)^2 + 1^2 ) = sqrt(3)sqrt(sqrt(3)^2 + 1^2 ) = sqrt(4)sqrt(sqrt(4)^2 + 1^2 ) = sqrt(5)sqrt(sqrt(5)^2 + 1^2 ) = sqrt(6)sqrt(sqrt(6)^2 + 1^2 ) = sqrt(7)sqrt(sqrt(7)^2 + 1^2 ) = sqrt(8)sqrt(sqrt(8)^2 + 1^2 ) = sqrt(9)sqrt(sqrt(9)^2 + 1^2 ) = sqrt(10)sqrt(sqrt(10)^2 + 1^2 ) = sqrt(11)sqrt(sqrt(11)^2 + 1^2 ) = sqrt(12)sqrt(sqrt(12)^2 + 1^2 ) = sqrt(13)sqrt(sqrt(13)^2 + 1^2 ) = sqrt(14)sqrt(sqrt(14)^2 + 1^2 ) = sqrt(15)sqrt(sqrt(15)^2 + 1^2 ) = sqrt(16)sqrt(sqrt(16)^2 + 1^2 ) = sqrt(17)


How do you calculate the golden ratio in math?

(1+sqrt(5))/2 This ratio is related to Fibonnacci numbers if you want to know more about it


What is the simplest square radical form for 50 and 3 square root of 8?

sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).


What is the square root of A squared B plus the square root of A B squared divided by the square root of AB?

The question is ambiguous because it could refer to [sqrt(A2B) + sqrt(AB2)]/sqrt(AB) = [A*sqrt(B) + B*sqrt(A)]/[sqrt(A)*sqrt(B)] = A/sqrt(A) + B/sqrt(B) = sqrt(A) + sqrt(B) or sqrt(A2B) + sqrt(AB2)/sqrt(AB) = A*sqrt(B) + B*sqrt(A)/[sqrt(A)*sqrt(B)] = A*sqrt(B) + B/sqrt(B) = A*sqrt(B) + sqrt(B) = sqrt(B)*(1 + A)