Math is the class, and sqrt() is the method.
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3.4086580994024981055126631335409sqrt(3)= 1.7320508075688772935274463415059sqrt(15) = 3.8729833462074168851792653997824sqrt(3) x sqrt(15) = 6.7082039324993690892275210061938 = sqrt(45) = 3 x sqrt(5)AnswerThis is an example of a question that's ambiguous because it hasn't been written mathematically. The above answer is for sqrt(3) x sqrt(15). Another interpretation of the question would be sqrt(3 x sqrt(15)), which has a different answer.
Vtop = sqrt(2)*Veffective so Veffective = Vtop / sqrt(2)
No commands in C; the name of function sqrt is sqrt (include math.h; and use -lm at linkage)
square root of the argument
Approximately 2.828427
sqrt 8 = sqrt 4 x 2 = 2 sqrt 2 But you wouldn't use "sqrt" to replace the proper math sign
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is the number 7 in real math a whole number
It is a Kangxi radical. The best way to display this radical is: sqrt(11)*sqrt(5)*sqrt(3). To get more information on these kinds of radicals one could visit websites such as Cool Math.
Expressed as a surd in its simplest form, sqrt(7.2) = 6 sqrt(5)/5 Expressed as a decimal, rounded to two decimal places, sqrt(7.2) = ±2.68
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sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).
sqrt(1^2 + 1^2 ) = sqrt(2)sqrt(sqrt(2)^2 + 1^2 ) = sqrt(3)sqrt(sqrt(3)^2 + 1^2 ) = sqrt(4)sqrt(sqrt(4)^2 + 1^2 ) = sqrt(5)sqrt(sqrt(5)^2 + 1^2 ) = sqrt(6)sqrt(sqrt(6)^2 + 1^2 ) = sqrt(7)sqrt(sqrt(7)^2 + 1^2 ) = sqrt(8)sqrt(sqrt(8)^2 + 1^2 ) = sqrt(9)sqrt(sqrt(9)^2 + 1^2 ) = sqrt(10)sqrt(sqrt(10)^2 + 1^2 ) = sqrt(11)sqrt(sqrt(11)^2 + 1^2 ) = sqrt(12)sqrt(sqrt(12)^2 + 1^2 ) = sqrt(13)sqrt(sqrt(13)^2 + 1^2 ) = sqrt(14)sqrt(sqrt(14)^2 + 1^2 ) = sqrt(15)sqrt(sqrt(15)^2 + 1^2 ) = sqrt(16)sqrt(sqrt(16)^2 + 1^2 ) = sqrt(17)
(1+sqrt(5))/2 This ratio is related to Fibonnacci numbers if you want to know more about it
sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).
The question is ambiguous because it could refer to [sqrt(A2B) + sqrt(AB2)]/sqrt(AB) = [A*sqrt(B) + B*sqrt(A)]/[sqrt(A)*sqrt(B)] = A/sqrt(A) + B/sqrt(B) = sqrt(A) + sqrt(B) or sqrt(A2B) + sqrt(AB2)/sqrt(AB) = A*sqrt(B) + B*sqrt(A)/[sqrt(A)*sqrt(B)] = A*sqrt(B) + B/sqrt(B) = A*sqrt(B) + sqrt(B) = sqrt(B)*(1 + A)