The sum of the currents through the branches of a simple parallel circuit is the current that flows through the voltage source.
Kirchoff's current law: The signed sum of the currents in a series circuit is zero. The sum of the currents in the branches represents one effective path, which is in series with the voltage source, so the two effective currents must be the same.
A well designed circuit should be able to operate over a range of voltages, not just at one voltage. Especially a circuit which is intended to be powered by a battery. As the battery starts to get used up, and the voltage drops, you want the circuit to operate as planned.
voltage is devided only in series circuit and is the same at the parallel circuit
Without specifics (are all the batteries end to end or are some loads between batteries, are all the loads the same resistive, capacitive or inductive value...), the generic answer is: the sum of supplied voltages must equal the sum of voltage drops across the loads.
It depends on what you mean by 'voltage'. For example, if you mean electromotive force (e.m.f.), then the internal resistance of a battery or generator will cause an internal voltage drop, resulting in the terminal voltage being lower than the open-circuit voltage and the greater the load, the lower the open-circuit voltage. On the other hand, if you are asking 'how' do you reduce voltage, then there are various ways. For a.c. voltages, we can use a step-down transformer. For d.c. voltages, we can use a variable resistor connected as a potentiometer, or a pair of fixed-value resistors to form a voltage divider.
The purpose of the battery in a circuit is to wive energy to the circuit
The voltage depends on how the two batteries are connected to one another. If they are connected in a series circuit (positive end to negative end) the voltage will double. If they are wired in a parallel circuit, (It
A well designed circuit should be able to operate over a range of voltages, not just at one voltage. Especially a circuit which is intended to be powered by a battery. As the battery starts to get used up, and the voltage drops, you want the circuit to operate as planned.
voltage is devided only in series circuit and is the same at the parallel circuit
The voltage across a battery in a parallel circuit is equal to the voltage across each bulb because Kirchoff's Voltage Law (KVL) states that the signed sum of the voltages going around a series circuit adds up to zero. Each section of the parallel circuit, i.e. the battery and one bulb, constitutes a series circuit. By KVL, the voltage across the battery must be equal and opposite to the voltage across the bulb. Another way of thinking about this is to consider that the conductors joining the battery and bulbs effectively have zero ohms resistance. By Ohm's law, this means the voltage across the conductor is zero, which means the voltage across the bulb must be equal to the voltage across the battery and, of course, the same applies for all of the bulbs.
The voltage for a potential relay will depend on the circuit that the relay is installed in. The relay can be made for low voltages (5v) to higher voltages (440.)
Without specifics (are all the batteries end to end or are some loads between batteries, are all the loads the same resistive, capacitive or inductive value...), the generic answer is: the sum of supplied voltages must equal the sum of voltage drops across the loads.
When a battery is added to a parallel circuit, the total voltage in the circuit increases as the new battery adds its voltage to the existing voltage sources. The total current in the circuit may also increase as the additional voltage motivates the charges to flow through the parallel branches of the circuit.
A mercury battery will provide constant voltage. A voltage regulator circuit will also.
Yes. The voltage is determined by the chemistry inside the battery.
It depends on what you mean by 'voltage'. For example, if you mean electromotive force (e.m.f.), then the internal resistance of a battery or generator will cause an internal voltage drop, resulting in the terminal voltage being lower than the open-circuit voltage and the greater the load, the lower the open-circuit voltage. On the other hand, if you are asking 'how' do you reduce voltage, then there are various ways. For a.c. voltages, we can use a step-down transformer. For d.c. voltages, we can use a variable resistor connected as a potentiometer, or a pair of fixed-value resistors to form a voltage divider.
The purpose of the battery in a circuit is to wive energy to the circuit
no