Yes.
AND operation
= f(A,B) = AB = A'f(0,B) + Af(1,B)
= A'(0B) + A(1B) = A'0 + AB
OR operation
- f(A,B) = A+B = A'f(0,B) + Af(1,B)
= A'(0+B) + A(1+B) = A'B + A1
NOT operation
- f(A) = A' = A'f(0) + Af(1)
= A'(1) + A(0)
we'll get 4 input mux cuz 2^4=16.... therefore the first 4 input mux has 16 o/p.. hence four-4 i/p mux are required to fill all 16 leads.
MUX(A, B, S) = A*S + B*S' NOT(A) = MUX(0, 1, A) = 0*A + 1*A' = A' From http://noyesno.net/
implement it. enough said.
Yes, a multiplexer (MUX) can be used to realize a logic function. By appropriately selecting the inputs and control signals of the MUX, it can generate the desired output for any given combination of input variables. Essentially, a MUX can be configured to implement any logic function by using its data inputs to represent the truth table of that function. This makes it a versatile tool in digital circuit design.
yes, given MUX in number To be implemented MUX 2:1MUX x 3 4:1MUX 4:1MUX x (4+1) 16:1MUX 4:1MUX x (16+4+1) 64:1MUX 8:1MUX x (8+1) 64:1MUX 8:1MUX x (32+4+1) 256:1MUX
what is a mux
Type your answer here... D0-D7 on 1st 8to1, D8-D15 on 2nd 8to1, S0,S1,S2 to both. The output from 1st 8to1 is D0 on the 2to1, the output from the 2nd 8to1 is D1 on the 2to1 and S3 to the 2to1. The 2to1 provides the final 16to 1 mutiplexed output, OK?
we'll get 4 input mux cuz 2^4=16.... therefore the first 4 input mux has 16 o/p.. hence four-4 i/p mux are required to fill all 16 leads.
As of July 2014, the market cap for McEwen Mining Inc. (MUX) is $706,322,326.55.
MUX(A, B, S) = A*S + B*S' NOT(A) = MUX(0, 1, A) = 0*A + 1*A' = A' From http://noyesno.net/
a mux has many i/ps & 1 o/p but a router connects many n/ws and the may or may not be of same kind a mux does not follow an algo but router follows algo such as dikakstra bellman ford or any other or a combination.......
A CMOS Mux is a piece of technology that is used to create integrated circuits that are used in electronics. The full name of 'CMOS' is Complementary Metal Oxide Semiconductor.
Alexander Maas goes by Mux.
Functionally, it was. It was nominally a constitutional monarchy with a separate legislative body called the Reichstag, but the kaiser had near complete power.
the quadrate and caudate lobes arises from the right lobe but are functionally distinct
1:50,000
The enable input in a multiplexer (MUX) determines whether the MUX is active or inactive. When the enable input is activated (usually set to high), the MUX can select one of its data inputs to pass through to the output. Conversely, when the enable input is deactivated (set to low), the MUX typically outputs a default value, often zero or a high-impedance state, effectively disconnecting the inputs from the output. This feature allows for better control over the signal flow and can prevent unwanted data from being passed through during certain operations.