Highly variable, depending on the type.
For example a 1N457 is rated for 79 volts, while a 1N4007 is rated for 1200 volts.
There are two diode ratings. One is the forward current rating, and the other is the reverse breakdown voltage rating. The forward current rating is the maximum current that the diode can conduct before failing, and the reverse breakdown voltage rating is the maximum reverse voltage that can be applied before failing. Of course, the reverse voltage rating has a different meaning in a zener diode, but this answer applies to ordinary diodes.
peak inverse voltage... piv of semiconductor is impoetant bcz we need to know after a peak voltage the diode get breakdown or damaged... so we need to know the peak voltage. piv is a point which withstands the maximum reverse biased voltage. after which the diode get damaged.
No, you must use one of three options depending upon your circuit and what you want to accomplish: 1. Use a transformer (ie; 24 volts into 12 volts). 2. Use a voltage regulator circuit. 3. Use a ZENER diode that is rated for the maximum voltage you desire in your circuit. Example: A 12 volt circuit with a 5 volt zener diode (the diode will only let a maximum 5 volts get through and will disipate the remaining voltage to ground. (requires proper design and resistor selection). ANSWER: YES ABSOLUTELY if there is a full wave rectifier removing one diode will reduce the voltage and reduce power too.
Peak Inverse Voltage, the maximum reverse bias (inverse) voltage that can be applied to the diode without damaging or destroying it. The work "peak" is used to remind you that when using the diode to rectify AC (or arbitrary waveforms) you must use the peak voltage, not the RMS voltage.
the High voltage rated diodes are power diodes while of low rating or normal voltage rating are considered to as ordinary / normal diode
Peak reverse voltage of a diode is the maximum reverse bias voltage can be applied to diode which does not cause break down.
The PIV (Peak Inverse Voltage) rating of a diode is the maximum voltage that you should apply to it in the reverse biased condition. Exceeding this voltage can destroy the diode.
If the applied voltage is greater than maximum forward voltage, the diode will get damaged..
The main difference between a 1n4004 and a 1n4007 are in the maximum RMS voltage, the maximum DC blocking voltage and the maximum repetitive peak reverse voltage. These are 280 and 700, 400 and 1000, and 400 and 1000 volts respectively.
A diode will provide saturating current if it reaches its Piv. What it should be well at least 1.5 of the applied reverse voltage. For AC at least 2 times to insure that the peak REVERSE voltage is blocked
There are two diode ratings. One is the forward current rating, and the other is the reverse breakdown voltage rating. The forward current rating is the maximum current that the diode can conduct before failing, and the reverse breakdown voltage rating is the maximum reverse voltage that can be applied before failing. Of course, the reverse voltage rating has a different meaning in a zener diode, but this answer applies to ordinary diodes.
The maximum voltage which can apply When diode in reverse bias..if it is exceed that voltage the diode may get damage.
piv:the maximum value of reverse voltage across a diode that occurs at the peak of the input cycle when the diode is reversed-biased.
due to high voltage across the diode ie more than piv of the diode or current flows more than maximum allowed range of diode.
peak inverse voltage... piv of semiconductor is impoetant bcz we need to know after a peak voltage the diode get breakdown or damaged... so we need to know the peak voltage. piv is a point which withstands the maximum reverse biased voltage. after which the diode get damaged.
No, you must use one of three options depending upon your circuit and what you want to accomplish: 1. Use a transformer (ie; 24 volts into 12 volts). 2. Use a voltage regulator circuit. 3. Use a ZENER diode that is rated for the maximum voltage you desire in your circuit. Example: A 12 volt circuit with a 5 volt zener diode (the diode will only let a maximum 5 volts get through and will disipate the remaining voltage to ground. (requires proper design and resistor selection). ANSWER: YES ABSOLUTELY if there is a full wave rectifier removing one diode will reduce the voltage and reduce power too.
Peak Inverse Voltage, the maximum reverse bias (inverse) voltage that can be applied to the diode without damaging or destroying it. The work "peak" is used to remind you that when using the diode to rectify AC (or arbitrary waveforms) you must use the peak voltage, not the RMS voltage.