Program in c to get the sum of n numbers present in an array using one dimensional array?

Answer 1

#include<stdio.h>

#include<conio.h>

main()

{

int num, n,sum=0,i=0;

printf("enter the number of elements to be added ");

scanf("%d",&n);

printf("enter %d numbers",n);

while(i<n)

{

scanf("%d",&num);

sum=sum+num;

i=i+1;

}

printf("the sum of %d numbers is %d",n,sum);

getch();

}

Answer 2

#include <stdio.h>

char input[1000];

float temp; /* temporary storage for numbers entered */

int num_count; /* number to divide total by */

float total; /* Total of numbers entered */

float average; /* 'total' divided by 'num_count' */

int main() {

/* Tell user what program does */

printf("I will find the average of however many numbers you enter.\n");

printf("Enter number now (00 to quit): ");

/* Accept first input from user */

fgets(input, sizeof(input), stdin);

temp = atof(input);

/* Initalize Variables */

num_count = 0;

total = 0.0;

average = 0.0;

while ( temp != 00.0 ) {

++num_count; /* increases with each number entered */

total += temp; /* adds all numbers entered to total */

printf("Enter next number now (00 to quit): ");

fgets(input, sizeof(input), stdin);

temp = atof(input);

}

average = ( total / num_count );

printf("You entered %d numbers. The average of those numbers is %f.\n", num_count, average);

return 0;

}

Answer 3

#include
#include
int i;
void main()
{
int sum(int b[],int n);
int sum_num,n,a[20];
clrscr();
printf("\nEnter the Items of an Array:");
scanf("%d",&n);
printf("Enter numbers into Array:");
for(i=0;iscanf("%d",&a[i]);
sum_num=sum(a,n);
printf("The Sum of Array Numbers is = %d",sum_num);
getch();
}
int sum(int b[],int n)
{
int s=0;
for(i=0;i{
s+=b[i];
}
return s;
}

output:

Enter the Items of an Array:5
Enter numbers into Array:
10
45
20
23
96
The Sum of Array Numbers is = 194

Answer 4

#include <iostream>

#include <vector>

using std::cout;

using std::cin;

using std::endl;

using std::vector;

int main()

{

int counter = 1;

cout << "Enter " << counter

<< " number (when you finish press any letter)";

vector<double> arrayOfData;

double tempVar = 0.0;

while (cin >> tempVar)

{

arrayOfData.push_back(tempVar);

++counter;

cout << "Enter " << conter << " number";

}

double sumOfElements = 0.0;

for (size_t i = 0; i < arrayOfData.size(); i++)

{

sumOfNumbers += arrayOfData.at(i);

}

cout << "\nAverage is: " << (sumOfNumbers/arrayOfData.size());

system("PAUSE");

return 0;

}

Answer 5

#include<stdio.h>

#include<conio.h>

main()

{

int marks[100];

int i,n,sum,average;

printf("enter the number of students");

scanf("%d",&n);

printf("enter %d student's marks",n);

sum=0;

for(i=0;i<n;i++)

{

scanf("%d",&marks[i]);

sum=sum+marks[i];

}

average=sum/n;

printf("the sum of the marks of %d studens is %d\n",n,sum);

printf("the average of %d students is %d\n",n,average);

getch();

}