#include
#include
void main()
{
char str1[80];
int i,j,flag=1;
printf("enter a word:");
gets(str1);
for(i=0,j= (strlen(str1)-1);i<=(strlen(str1)-1),j>=0;i++,j--)
{
if(str1[i]!=str1[j])
flag=0;
}
if(flag)
printf("palindrome");
else
printf("not a palindrome");
}
/*To check whether a string is palindrome*/includeincludevoid main () { int i,j,f=0; char a[10]; clrscr (); gets(a); for (i=0;a[i]!='\0';i++) { } i--; for (j=0;a[j]!='\0';j++,i--) { if (a[i]!=a[j]) f=1; } if (f==0) printf("string is palindrome"); else printf("string is not palindrome"); getch (); }
import java.util.Scanner; public class Palindrome{ public static void main(String[] args){ String front; String back =""; char[] failure; String backwards; Scanner input=new Scanner(System.in); System.out.print("Enter a word: "); front=input.next(); front=front.replaceAll(" ", ""); failure=front.toCharArray(); for (int i=0; i<failure.length; i++){ back=failure[i] + back; } if (front.equals(back)){ System.out.print("That word is a palindrome"); }else System.out.print("That word is not a palindrome"); }}
sdfdg
Palindrome number is a number like 121 which remains the same when its digits are reversed. To find this number in a simple java program, just follow the below way. sum = 0; while(n>0) { r=n % 10; sum=concat(r); n=n / 10; } print r;
use the strrev() function on the given string and compare with original string.If both are equal they are palindromes else not.
To check if a string is a palindrome, point to each end of the string and work inwards towards the middle. If the characters pointed at differ, the string is not a palindrome. When the pointers meet or cross each other, the string is a palindrome. Note that the string cannot contain whitespace or punctuation and comparisons must not be case-sensitive.
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char a[15],b[15]; printf("Enter the string\n"); scanf("%s",&a); strcpy(b,a); strrev(a); if(strcmp(a,b)==0) printf("The String is a palindrome"); else printf("The String is not a palindrome"); }
You can do this: <?php if ( $word === strrev( $word ) ) { echo "The word is a palindrome"; } else { echo "The word is not a palindrome"; }
/*To check whether a string is palindrome*/includeincludevoid main () { int i,j,f=0; char a[10]; clrscr (); gets(a); for (i=0;a[i]!='\0';i++) { } i--; for (j=0;a[j]!='\0';j++,i--) { if (a[i]!=a[j]) f=1; } if (f==0) printf("string is palindrome"); else printf("string is not palindrome"); getch (); }
It is a simple program. i think u may understand it :#include#include#includevoid main(){char s[10]=answers.com;char x[10];int a;clrscr();strcpy(x,s);strrev(s);a=strcmp(s,x);if(a==0){printf("the entered string is palindrome");}else{printf("the entered string is not palindrome");}output:given string is not palindrome
You could use a function like this:function isPalindrome($string) {$string = strtolower($string);return (strrev($string) == $string) ? true : false;}and then to check a palindrome call an if statement like so:if(isPalindrome($test)) {echo $test.' is a palindrome';}else {echo $test.' is not a palindrome';}
Reverse the string and compare it to the original. If they match, then it is a palindrome.
import java.util.Scanner; public class Palindrome{ public static void main(String[] args){ String front; String back =""; char[] failure; String backwards; Scanner input=new Scanner(System.in); System.out.print("Enter a word: "); front=input.next(); front=front.replaceAll(" ", ""); failure=front.toCharArray(); for (int i=0; i<failure.length; i++){ back=failure[i] + back; } if (front.equals(back)){ System.out.print("That word is a palindrome"); }else System.out.print("That word is not a palindrome"); }}
sdfdg
One efficient way to find the longest palindrome subsequence in Java is by using dynamic programming. This involves creating a 2D array to store the lengths of palindrome subsequences for different substrings of the input string. By iterating through the string and filling in the array based on the palindrome properties, you can determine the longest palindrome subsequence.
Palindrome number is a number like 121 which remains the same when its digits are reversed. To find this number in a simple java program, just follow the below way. sum = 0; while(n>0) { r=n % 10; sum=concat(r); n=n / 10; } print r;
Yes, you can use regex to determine if a given string is a palindrome by reversing the string and then comparing it to the original string using regex.