Programme to swap two arrays in C programming?

Answer 1

#include <iostream>

int main()

{

// Declare and initialise an array with two elements.

int A[2]={1,2};

// Output the array values:

std::cout<<"Before swap:\t"<<"A[0]="<<A[0]<<", A[1]="<<A[1]<<std::endl;

// Swap the array values.

A[0]^=A[1]^=A[0]^=A[1];

// Output the array values:

std::cout<<"After swap:\t"<<"A[0]="<<A[0]<<", A[1]="<<A[1]<<std::endl;

return(0);

}

Output:

Before swap: A[0]=1, A[1]=2

After swap: A[0]=2, A[1]=1

Answer 2

#include

using std::cin;
using std::cout;
using std::endl;

int main()
{
const int myArraySize = 5;
double myArray1[myArraySize] = {23, 54, 23, 76, 5};
cout << "Your first array is: " << endl;
for (int i(0); i < myArraySize; i++)
{
cout << myArray1[i] << endl;
}

double myArray2[myArraySize] = {67, 56, 3, 673, 345};
cout << "Your second array is: " << endl;
for (int i(0); i < myArraySize; i++)
{
cout << myArray2[i] << endl;
}

double swapArrays[myArraySize] = {0.0};
for (int i(0); i < myArraySize; i++)
{
swapArrays[i] = myArray1[i];
myArray1[i] = myArray2[i];
myArray2[i] = swapArrays[i];
}

cout << "Your first array after swapping is: " << endl;
for (int i(0); i < myArraySize; i++)
{
cout << myArray1[i] << endl;
}

cout << "Your second array after swapping is: " << endl;
for (int i(0); i < myArraySize; i++)
{
cout << myArray2[i] << endl;
}

system("PAUSE");
return 0;
}