Refer to the first and last elements by index, and work towards the middle until the indices meet or pass each other, swapping the element values as you go.
Use the C++ getline() function from the standard library.
input is the << operator and output is the >> operator
The following program prints every second character of the input in reverse order. #include<iostream> #include<sstream> int main() { std::cout << "Input:\t"; std::string input = ""; std::getline (std::cin, input); if (input.size()) { std::cout << "Output:\t"; unsigned index = input.size() / 2 * 2; do { index -= 2; std::cout << input[index]; } while (index); std::cout << std::endl; } }
map.clear()
That is STANDARD input and STANDARD output. By default, standard input is the keyboard, and standard output is the screen. Standard I/O is set by the operating system, though it may be redirected by script invocation or system commands within the C/C++ program itself. You could, for instance, set standard output to a printer or a file in lieu of a screen. You should also Google Standard Error.
For basic input and output in C++: #include
Input a variable.
cin.clear();
Use the C++ getline() function from the standard library.
input is the << operator and output is the >> operator
The following program prints every second character of the input in reverse order. #include<iostream> #include<sstream> int main() { std::cout << "Input:\t"; std::string input = ""; std::getline (std::cin, input); if (input.size()) { std::cout << "Output:\t"; unsigned index = input.size() / 2 * 2; do { index -= 2; std::cout << input[index]; } while (index); std::cout << std::endl; } }
Use an SLR parser algorithm.
A B plus C plus D plus E plusorA B C D E plus plus plus plusor variations.
No. In C++ with <iostream>, cin is a prefedined class that represents stdin, so it is an input identifier.
map.clear()
I guess you mean either input/output/inout/append or binary/text.
Quick 'n' dirty example (use at own risk). Enter 10 numbers (range: 0-9) and print in reverse order. #include <stdio.h> int main{ BYTE element[10]; memset( &element[0], 10, 10 ); int i; for( i = 0; i < 10; ++i ) while( element[i] < 0 && element[i] > 9 ) cin >> element[i]; for( i = 10; i > 0; ) cout << element[--i]; return 0; };