int RevNum( int num )
{
const int base = 10;
int result = 0;
int remain = 0;
do
{
remain = num % base;
result *= base;
result += remain;
} while( num /= base);
return( result );
}
To reverse a number, first convert the number to a string, then reverse the string. Given your number consists of alphanumeric characters, the number must already be a string so simply reverse the string: #include<string> using std::string; string reverse (const string& s) { string str {}; for (auto c : s) str.insert (str.begin(), c); return str; } int main () { std::cout << "Enter a number: "; string s {}; std::cin >> s; std::cout << "The number in reverse is: " << reverse (s); }
void main(){int *n,a,r=0;clrscr();printf("enter any no to get its reverse: ");scanf("%d",&*n);while(*n>=1){a=*n%10;r=r*10+a;*n=*n/10;}printf("reverse=%d",r);getch();}Output:enter any no to get its reverse: 456reverse=654
#include #include void main() { int rev num=0; while(num>0) { rev num=rev num*10+num%10; num=num%10; } return rev_num; } int main(); { int num=4562; printf("reverse of number is%d",reverse digit(num)); getch(); return o; }
#include <stdio.h> int main() { int number, temp; printf("enter the number"); scanf("%d",&number); printf("\n reverse of %d",number); while(number>0) { temp=temp*10+number%10; number=number/10; } printf(" is %d",temp); }
write a c++ program to convert binary number to decimal number by using while statement
The steps for using a free reverse phone number lookup are: go to a website like Reverse Number Direct, type in the relevant information and then you'll get results.
unsigned reverse (unsigned num) { unsigned rev = 0; while (num) { rev *= 10; rev += num % 10; num /= 10; } return rev; }
To check if a number is a palindrome, reverse the number and see if it is equal to the original number. If so, the number is a palindrome, otherwise it is not. To reverse a number, use the following function: int reverse(int num, int base=10) { int reverse=0; while( num ) { reverse*=base; reverse+=num%base; num/=base; } return(reverse); }
An example of an algorithm that will reverse a number is written as such, digit reverse(num), while (num>0) then, digit =num%10. This particular algorithm divides a number by 10 until the original number from the LSD is found.
When using a reverse search phone number the person you are calling can tell who you are without having to look you up manually, this will increase the chances of calls from reputable companies being answered.
To reverse a number, first convert the number to a string, then reverse the string. Given your number consists of alphanumeric characters, the number must already be a string so simply reverse the string: #include<string> using std::string; string reverse (const string& s) { string str {}; for (auto c : s) str.insert (str.begin(), c); return str; } int main () { std::cout << "Enter a number: "; string s {}; std::cin >> s; std::cout << "The number in reverse is: " << reverse (s); }
void main(){int *n,a,r=0;clrscr();printf("enter any no to get its reverse: ");scanf("%d",&*n);while(*n>=1){a=*n%10;r=r*10+a;*n=*n/10;}printf("reverse=%d",r);getch();}Output:enter any no to get its reverse: 456reverse=654
#include #include void main() { int rev num=0; while(num>0) { rev num=rev num*10+num%10; num=num%10; } return rev_num; } int main(); { int num=4562; printf("reverse of number is%d",reverse digit(num)); getch(); return o; }
Reverse the digits then check of the new number is the same as the original number.
Try using a reverse phone search like on whitepages.com or searching the number on Google
You can check this website http://www.whitepages.com/reverse_phone By using this website you have to look for the tab reverse phone then put the phone number and click find.
The number of protons can not be changed in an atom, while the number of electrons can be.