400 ohms
If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
If a circuit containing five 50-ohm resistors has a total resistance of 10 ohms, the resistors must be connected in parallel. In a parallel configuration, the total resistance is calculated using the formula ( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} ). For five 50-ohm resistors in parallel, the total resistance indeed comes out to 10 ohms.
The total DC resistance is (33+47) = 80 ohms.The total reactance is j(60+30) = j90 ohms.The total impedance of the string is [ 80 + j90 ] ohms,= 120.4 ohms at a phase angle of 48.37 degrees (both numbers rounded).
The total effective resistance of resistors in series is the sum of the individual resistances.Three 60-ohm resistors in series have a total effective resistance of (60 + 60 + 60) = 180 ohms.
30 ohms
Two eight-ohm resistors in series would have a total resistance of 16 ohms. Two eight-ohm resistors in parallel would have a total resistance of four ohms.
50 ohms
If the circuit consists of resistors only, you simply add the values of all the resistors, in ohms.
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
28 + 56 = 84 ohms
The total effective resistance of resistors in series is the sum of the individual resistances.Three 60-ohm resistors in series have a total effective resistance of (60 + 60 + 60) = 180 ohms.
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
If a circuit containing five 50-ohm resistors has a total resistance of 10 ohms, the resistors must be connected in parallel. In a parallel configuration, the total resistance is calculated using the formula ( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} ). For five 50-ohm resistors in parallel, the total resistance indeed comes out to 10 ohms.
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
2000 ohms
Resistors placed in series create a total resistance that is found by simply adding the values of the resistors. (Knowing the applied voltage isn't necessary to solve this problem.) Rt = R1 + R2 + R3 = 2 ohms + 4 ohms + 6 ohms = 12 ohms