To print automorphic number in c plus plus language?

Answer 1

#include <stdio.h>

main (int argc, char **argv)

{

long inx, num, n, ns, r1, r2;

num = atol(argv[1]);

printf("num=%ld\n", num);

for (inx = 1; inx < num; inx++)

{

n = inx;

ns = n*n;

while (n > 0)

{

r1 = n%10;

r2 = ns%10;

if (r1 != r2) break;

n = n/10;

ns = ns/10;

}

if (n == 0)

{

printf("%ld is automorphic\n", inx);

}

}

}

Answer 2

#include<iostream>

#include<sstream>

bool is_automorphic(const size_t num)

{

std::stringstream ss;

std::string strnum, strsqr;

size_t square = num*num;

ss << num;

ss >> strnum;

ss.clear();

ss << square;

ss >> strsqr;

return strnum==strsqr.substr(strsqr.size()-strnum.size(),strnum.size());

}

void process (const size_t num)

{

if (is_automorphic(num))

std::cout << "The number " << num << " is automorphic." << std::endl;

else

std::cout << "The number " << num << " is not automorphic." << std::endl;

}

int main()

{

process (4);

process (5);

process (6);

process (76);

process (9376);

}