Using while loop, write a program which calculates the product of digits from 1 to 5 and also show these no's vertically.
#include<iostream> unsigned sum_of_digits(unsigned num) { unsigned sum = 0; do { sum += num%10; } while (num/=10); return sum; } int main() { unsigned number = 12345; unsigned sum = sum_of_digits (number); std::cout << "Sum of digits in " << number << " is " << sum << std::endl; }
public static void main(String[] args) { int val = 100; int val1 = 50; System.out.println("Number of digits in " + val + " is: " + new String(val + "").length()); System.out.println("Number of digits in " + val1 + " is: " + new String(val1 + "").length()); }
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
That is almost like asking how many digits are in a number. The only limit is the amount of space available for a barcode. Even the size of most scanners does not create an absolute limit because there are barcode readers that look like a pen and read the barcode information serially (one digit at a time). Perhaps you would like to rephrase your question to find out about a particular barcode application. For example, Universal Product Codes (UPC's) usually have ten digits. The first five identify the manufacturer or distributor, and the other five identify a unique product, including a particular size or quantity of the product. UPC's do not contain any price information; that information is cross referenced by the store's computer after the UPC is scanned.
#include<stdio.h> #include<conio.h> main() { int n,s,r,t; clrscr(); printf("enter n"); scanf("%d",&n); s=0;t=0; while(n!=0) { r=n%10; { if(r%2!=0) t=t+r; if(r%2==0) s=s+r; } n=n/10; } printf("sum of even position digits%d\n",s); printf("sum of odd position digits%d\n",t); getch(); }
Mutilply the values of the digits.
88
two
52 is a number whose digits have a product of 10.
22
You had me until "product." The product of 4 digits can't be prime.
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
When using significant digits, the product has only the number of significant digits as the lowest number in the factors. "20" has two significant digits and "310" has three. Therefore, the product has to have two significant digits. 310 × 20 = 6200 6200 already has two significant digits.
The PEC must be 8 digits ending in a letter.
67/72 of them.
400 x 4 = 1600 Therefore, four digits.
from 3 digits (10x10) to 4 digits (99X99)