Using while loop, write a program which calculates the product of digits from 1 to 5 and also show these no's vertically.
To write a program that inputs a number and displays the digits absent in it, you can follow these steps: Convert the input number into a set of its digits. Create a set of all possible digits (0-9). Subtract the set of digits from the complete set to find the missing ones. Display the missing digits. Here’s a simple example in Python: number = input("Enter a number: ") present_digits = set(number) all_digits = set('0123456789') missing_digits = all_digits - present_digits print("Missing digits:", ''.join(missing_digits))
#include<iostream> unsigned sum_of_digits(unsigned num) { unsigned sum = 0; do { sum += num%10; } while (num/=10); return sum; } int main() { unsigned number = 12345; unsigned sum = sum_of_digits (number); std::cout << "Sum of digits in " << number << " is " << sum << std::endl; }
public static void main(String[] args) { int val = 100; int val1 = 50; System.out.println("Number of digits in " + val + " is: " + new String(val + "").length()); System.out.println("Number of digits in " + val1 + " is: " + new String(val1 + "").length()); }
In QBASIC, you can write a simple program to input the number 64751315 and sum its digits as follows: DIM sum AS INTEGER sum = 0 INPUT "Enter a number: "; number FOR i = 1 TO LEN(number) sum = sum + VAL(MID$(number, i, 1)) NEXT PRINT "The sum of the digits is "; sum This program prompts the user to input a number, iterates through each digit, converts it to an integer, and adds it to the total sum, which is then printed out.
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
Mutilply the values of the digits.
88
two
52 is a number whose digits have a product of 10.
22
You had me until "product." The product of 4 digits can't be prime.
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
When using significant digits, the product has only the number of significant digits as the lowest number in the factors. "20" has two significant digits and "310" has three. Therefore, the product has to have two significant digits. 310 × 20 = 6200 6200 already has two significant digits.
The PEC must be 8 digits ending in a letter.
Ignore the decimal points and multiply the numbers to give the product: 308*29 = 8932Count the number of digits AFTER the decimal points in the two numbers. Two in the first and one in the second, making three in all.That is the number of digits after the decimal point that you want in the answer. So insert the decimal point that many digits from the end of the product.Thus 8932 becomes 8.932Done!
The product of a 4-digit multiplicand and a 1-digit multiplier can have either 4 or 5 digits. If the 4-digit number is multiplied by a multiplier of 1 to 9, the product will typically have 4 digits. However, if the multiplicand is multiplied by 10 (the maximum value for a 1-digit number), the product can reach a maximum of 5 digits. Thus, the product can range from 4 to 5 digits, depending on the specific numbers involved.
400 x 4 = 1600 Therefore, four digits.