The difference between the Class 365 and Class 465, 466 is basically the cost.
480
The difference b/w the prime generator & standby generator is that the prime generator is used for 24/7/365, while the standby generators are only used in emergency cases, if we used standby generators for more than 24 hours continuously, then it will be overheated for sure.
#include <stdio.h> int main () { int year,days,d; printf("year?"); scanf("%d",&year); days = 365*year + (year-1)/4 - (year-1)/100 + (year-1)/400 ; d=days%7;//to find which day of week if(d==1) printf("\n\n\tmonday"); else if(d==2) printf("\n\n\ttuesday"); else if(d==3) printf("\n\n\twednesday"); else if(d==4) printf("\n\n\tthursday"); else if(d==5) printf("\n\n\tfriday"); else if(d==6) printf("\n\n\tsaturday"); else if(d==0) printf("\n\n\tsunday"); return(0); }
#include<iostream> void num_to_years_weeks_days( unsigned num, unsigned& years, unsigned& weeks, unsigned& days) { years = num / 365; num -= years * 365; weeks = num / 7; num -= weeks * 7; days = num; } int main() { unsigned years, weeks, days; unsigned num = 1000; num_to_years_weeks_days(num, years, weeks, days); std::cout << num << " days is " << years << " years, " << weeks << " weeks and " << days << " days\n" << std::endl; num = 12345; std::cout << num << " days is " << years << " years, " << weeks << " weeks and " << days << " days\n" << std::endl; }
#include<stdio.h> #include<conio.h> #include<time.h> time_t time(time_t *t); main() { int y2,m2,d2,y,m,d; time_t t = time(NULL); struct tm tm = *localtime(&t); printf("Time now: %d-%d-%d %d:%d:%d\n", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec); y2=tm.tm_year+1900; m2=tm.tm_mon+1; d2=tm.tm_mday; printf("Enter the Reference Date in DD MM YY format\n"); scanf("%d%d%d",&d,&m,&y); int loop,total_days = 0,days_in_a_year; int day,month,year; int month_days[] = {31,28,31,30,31,30,31,31,30,31,30,31}; printf("\n%d\n%d\n%d\n",(y2-y),(m2-m),(d2-d)); printf("%d",month_days[m]); if(((y2-y)==0&&(m2-m)<1&&(d2<d))(y2<y)(m<1)(m>12)(d<0)(d>month_days[m-1])) { printf("\nInvalid Reference Date\n"); } else { total_days=month_days[m-1]-d; if((m==2)&&((y%4)==0)) total_days+=1; for(int i=m;i<12;i++) { if((y%4==0)&&i==1) total_days+=1; total_days+=month_days[i]; } for(int year=y+1;year<y2;year++) { if(year%4==0) total_days+=366; else total_days+=365; } for(int i=0;i<m2-1;i++) { if((y2%4==0)&&i==1) total_days+=1; total_days+=month_days[i]; } total_days+=d2; if((y2==y)&&(y%4==0)) total_days-=366; if((y2==y)&&(y%4!=0)) total_days-=365; } printf("\nThe date difference is %d\n",total_days); getch(); }
5646442324
The difference between 365 and 36 is 329. Add 70 is 399.
3
1344 − 979 = 365
25 cubic inches...of lovely stroke.
The difference between 365 days and 1 year is approximately one quarter (1/4) of a day. A year is about 365.25 days long. This is why there is a leap year every fourth year, when an axtra day is added to February.
A year is 365 days and a century is 100 years. A millenium is 1000 years
ok let's try this! on any given date, probability that there is a student with a birthday is 30/365, so prob. that two students have that birthday is (30/365)^2. Tell me if I'm wrong, somebody! So the problem that this does NOT happen is 1-(30/365)^2 which is 0.9932445... I'm not sure about this next bit: there are 365 days in which this probably won't occur, does that make a difference?
Interest that is based on a 360-day year instead of a 365-day year. In contrast, exact interest is based on a 365-day year. If large sums of money are involved, the difference can be significant
365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.
100 and 363, 101 and 364, 102 and 365, ... Take your pick!
If the cost is $365.00 per credit, then a four credit course would cost $1,4600.00.