Various energy losses occur in Transformers:
Copper losses, the resistance to the current flow in the windings which heats the conductors.
Iron losses, which are of two kinds:
That is why transformer cores are generally made of lots of separate thin "laminations" which are insulated from one another by being bonded together using an epoxy resin adhesive.
These are reduced by making the laminations of silicon steels, which have lower hysteresis losses than plain iron.
Together all these losses lead to a total efficiency of about 97 to 98%, which will alter depending upon the load current that the transformer is supplying.
The no load losses are the losses caused by energizing the transformer. These are constant losses, regardless of loading. This in effect tells you the efficiency of the transformer. (Power in) - (no load losses) = (Power out)
Ideal transformer is useful in understanding the practical transformer..i does't have losses...
there are several losses in a transformer that prevent it from attaining 100% efficiency. One is core loss, which can be divided into Hysteresis losses, Eddy currents and Magnetostriction loses. see for more details http://en.wikipedia.org/wiki/Transformer#Energy_losses
The transformer can be tested on open and short circuit to find the iron losses and copper losses separately, which uses a fraction of the power than having to run the transformer on full-load.
No load losses are real power losses (in watts, not vars), so I'm not sure what you're talking about. If you're trying to parallel a transformer with another one to try to cancel out no load losses, you can't do this. These losses are also called core losses and are the price you pay to energize a transformer.
The no load losses are the losses caused by energizing the transformer. These are constant losses, regardless of loading. This in effect tells you the efficiency of the transformer. (Power in) - (no load losses) = (Power out)
When the frequency of a transformer is increased, the core losses of the transformer increase due to increased eddy current losses and hysteresis losses. This results in a rise in temperature of the transformer. Additionally, higher frequency can affect the impedance of the transformer and alter the voltage regulation and efficiency.
Ideal transformer is useful in understanding the practical transformer..i does't have losses...
Losses due to loading. As more load (more current) is put on a transformer, these losses will increase. They are often referred to as I2R (or I^2*R) losses.
Core losses are losses in the magnetic system of the transformer, such as eddy currents in the core, hysteresis losses, etc. Because of this, the losses are constant, regardless of load, assuming voltage and frequency stay fixed.
For a single-phase transformer, maximum efficiency typically occurs at around 50-70% of the rated load. Operating the transformer at this load range minimizes losses and improves efficiency. Going below or above this range can decrease efficiency and increase losses in the transformer.
there are several losses in a transformer that prevent it from attaining 100% efficiency. One is core loss, which can be divided into Hysteresis losses, Eddy currents and Magnetostriction loses. see for more details http://en.wikipedia.org/wiki/Transformer#Energy_losses
Well, isn't that a happy little coincidence! If iron losses and copper losses are equal in a transformer, it means that the transformer is operating at its maximum efficiency. This balance allows the transformer to work smoothly and effectively, creating a harmonious flow of energy. Just like when all the colors blend together perfectly on our canvas, creating a beautiful masterpiece.
The transformer can be tested on open and short circuit to find the iron losses and copper losses separately, which uses a fraction of the power than having to run the transformer on full-load.
No load losses are real power losses (in watts, not vars), so I'm not sure what you're talking about. If you're trying to parallel a transformer with another one to try to cancel out no load losses, you can't do this. These losses are also called core losses and are the price you pay to energize a transformer.
Transformer
Iron losses are due to energization of the transformer; they do not depend on the loading of the transformer. They will vary depending on the voltage applied to the transformer. The best model of this is a parallel connection to the ideal transformer winding.