The smallest value is -32,768 and the maximum is 32,767
final double[] ns = new double[10]; final Random rnd = new Random(System.currentTimeMillis()); // Fill... for (int i = 0; i < ns.length; ++i) { ns[i] = rnd.nextDouble(); } // Get largest/smallest... double largest = Double.MIN_VALUE; double smallest = Double.MAX_VALUE; for (double n : ns) { if (n > largest) { largest = n; } if (n < smallest) { smallest = n; } } // largest and smallest are now the proper values.
It means that you can only store values like Integer, String etc in a Vector and not values like int, float etc. int, float, double etc are primitive data types. collections by their default behavior can hold only objects and not primitives.
Primitive variables are variables that are not objects and carry primitive values like numbers, boolean etc. The primitive data types in java are:intbytefloatcharlongbooleanshortdouble
#include #include #include int main(int argc, char *argv[]){int n, smallest, largest, sum, temp;if(argc < 2){printf("Syntax: foo val1[val2 [val3 [...]]]\n");exit(1);}smallest = largest = sum = atoi(argv[1]);for(n = 2; n < argc; n++){temp = atoi(argv[n]);if(temp < smallest) smallest = temp;if(temp > largest) largest = temp;sum += temp;}printf("Smallest: %i\nLargest: %i\nAverage: %i\n", smallest, largest, sum / (argc - 1));return 0;}
No. In Java, you can store a limited range of values in an integer. Specifically, integers are 32-bit signed values which can store values in the range [-231, 231-1]. If you need to store more values, consider using a long integer [-263, 263-1] or the BigInteger class (which can store arbitrary-precision values).
You find the the smallest and largest values. The interval is the largest minus the smallest.
Span
It is the largest value less the smallest one.
The range.
final double[] ns = new double[10]; final Random rnd = new Random(System.currentTimeMillis()); // Fill... for (int i = 0; i < ns.length; ++i) { ns[i] = rnd.nextDouble(); } // Get largest/smallest... double largest = Double.MIN_VALUE; double smallest = Double.MAX_VALUE; for (double n : ns) { if (n > largest) { largest = n; } if (n < smallest) { smallest = n; } } // largest and smallest are now the proper values.
If possible, find the largest and smallest possible values of the variable under study. Then the range = Largest Value minus Smallest Value.
The set of positive integers is {1, 2, 3, 4, 5, ...}. Because the values approach positive infinity there is no largest positive integer. If you pick any positive integer, you can always create a larger one by simply adding 1 to it. So there can be no largest positive integer.
take the largest number in the sample and subtract the smallest number that is the range
Assume that the first one is the largest.Compare another integer with the current largest. If it is larger than the current largest, it becomes the new largest.Repeat the second point for every integer.At the end, the current largest is the overall largest.
The mean of the 10th and 11th values
The mean of the 6th and 7th values
The mean of the 3rd and 4th values