0
A frac technician, or fracturing technician, is responsible for the operation and maintenance of equipment used in hydraulic fracturing, a process that enhances oil and gas extraction from underground reservoirs. They prepare and transport fracturing fluids, monitor pressure levels, and ensure safety protocols are followed during operations. Frac technicians work closely with engineers and field crews to optimize the efficiency of the fracturing process and troubleshoot any issues that arise on-site. Their role is crucial for the successful execution of fracking projects in the energy sector.
What else can I help you with?
What is the lowest resistance that can be obtained by combining four coils of resistors of 4 ohm 8 ohm12ohm and 24 ohm?
To achieve the lowest resistance when combining resistors, you should connect them in parallel. The formula for the total resistance ( R_t ) of resistors in parallel is given by ( \frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} ). For the given resistors (4 ohms, 8 ohms, 12 ohms, and 24 ohms), this results in ( \frac{1}{R_t} = \frac{1}{4} + \frac{1}{8} + \frac{1}{12} + \frac{1}{24} = \frac{13}{24} ), leading to a total resistance ( R_t ) of approximately 1.85 ohms.
What is the total inductance of a circuit that contains two 22 mH inductors in parallel?
To find the total inductance ( L_t ) of two inductors in parallel, you can use the formula: [ \frac{1}{L_t} = \frac{1}{L_1} + \frac{1}{L_2} ] For two identical inductors of 22 mH, this simplifies to: [ \frac{1}{L_t} = \frac{1}{22 , \text{mH}} + \frac{1}{22 , \text{mH}} = \frac{2}{22 , \text{mH}} = \frac{1}{11 , \text{mH}} ] Thus, the total inductance ( L_t ) is 11 mH.
3 inductors connected in parallel. Inductor 1 has an inductance of 0.06 H inductor 2 has an inductance of 0.05 H and inductor 3 has an inductance of 0.1 H. What is the total inductance of this circuit?
When inductors are connected in parallel, the total inductance (L_total) can be calculated using the formula: (\frac{1}{L_{total}} = \frac{1}{L_1} + \frac{1}{L_2} + \frac{1}{L_3}). For the given inductors, this becomes: (\frac{1}{L_{total}} = \frac{1}{0.06} + \frac{1}{0.05} + \frac{1}{0.1}). Calculating this yields (L_{total} \approx 0.017 H) or 17 mH.
When n capacitors of equal capacitances c are connected in series the effective capacitance is?
When ( n ) capacitors of equal capacitance ( c ) are connected in series, the effective or equivalent capacitance ( C_{\text{eq}} ) is given by the formula: [ \frac{1}{C_{\text{eq}}} = \frac{1}{c} + \frac{1}{c} + \ldots + \frac{1}{c} = \frac{n}{c} ] Thus, the effective capacitance is: [ C_{\text{eq}} = \frac{c}{n} ] This shows that the effective capacitance decreases as the number of capacitors in series increases.
What is the technician to verb?
There is no verb form of technician
What is 3 23 plus 2 34?
To add the mixed numbers (3 \frac{23}{24}) and (2 \frac{3}{4}), first convert (2 \frac{3}{4}) to a fraction: (2 \frac{3}{4} = 2 + \frac{3}{4} = \frac{8}{4} + \frac{3}{4} = \frac{11}{4}). Now, convert (3 \frac{23}{24}) to an improper fraction: (3 \frac{23}{24} = \frac{72}{24} + \frac{23}{24} = \frac{95}{24}). Next, find a common denominator (which is 24) and convert (\frac{11}{4}) to (\frac{66}{24}). Finally, add the fractions: (\frac{95}{24} + \frac{66}{24} = \frac{161}{24}), which simplifies to (6 \frac{13}{24}). Thus, (3 \frac{23}{24} + 2 \frac{3}{4} = 6 \frac{13}{24}).
What is 9 12th's plus 2 fourths?
To add ( \frac{9}{12} ) and ( \frac{2}{4} ), first simplify ( \frac{2}{4} ) to ( \frac{1}{2} ) or ( \frac{6}{12} ) for a common denominator. Now, ( \frac{9}{12} + \frac{6}{12} = \frac{15}{12} ). This can be simplified to ( \frac{5}{4} ) or ( 1 \frac{1}{4} ).
What is 2 fifths plus 2 sevenths?
To add ( \frac{2}{5} ) and ( \frac{2}{7} ), we first find a common denominator, which is 35. Converting the fractions, we have ( \frac{2}{5} = \frac{14}{35} ) and ( \frac{2}{7} = \frac{10}{35} ). Adding these gives ( \frac{14}{35} + \frac{10}{35} = \frac{24}{35} ). Therefore, ( \frac{2}{5} + \frac{2}{7} = \frac{24}{35} ).
What is eight thirds plus negative nines forths?
To add ( \frac{8}{3} ) and ( -\frac{9}{4} ), first find a common denominator, which is 12. Rewrite the fractions: ( \frac{8}{3} = \frac{32}{12} ) and ( -\frac{9}{4} = -\frac{27}{12} ). Now add them: ( \frac{32}{12} - \frac{27}{12} = \frac{5}{12} ). Therefore, ( \frac{8}{3} + -\frac{9}{4} = \frac{5}{12} ).
What is 3 fifths plus 3 eighths?
To add ( \frac{3}{5} ) and ( \frac{3}{8} ), first find a common denominator, which is 40. Converting the fractions, ( \frac{3}{5} = \frac{24}{40} ) and ( \frac{3}{8} = \frac{15}{40} ). Adding these together gives ( \frac{24}{40} + \frac{15}{40} = \frac{39}{40} ). Therefore, ( \frac{3}{5} + \frac{3}{8} = \frac{39}{40} ).
What is the sum 3 4 plus 5 16?
To find the sum of ( \frac{3}{4} ) and ( \frac{5}{16} ), first convert ( \frac{3}{4} ) to a fraction with a denominator of 16: ( \frac{3}{4} = \frac{12}{16} ). Now, add ( \frac{12}{16} ) and ( \frac{5}{16} ): ( \frac{12}{16} + \frac{5}{16} = \frac{17}{16} ). Therefore, the sum is ( \frac{17}{16} ) or ( 1 \frac{1}{16} ).
What is 3 over 4 plus 1 over 5?
To add ( \frac{3}{4} ) and ( \frac{1}{5} ), first find a common denominator, which is 20. Convert ( \frac{3}{4} ) to ( \frac{15}{20} ) and ( \frac{1}{5} ) to ( \frac{4}{20} ). Now, add the fractions: ( \frac{15}{20} + \frac{4}{20} = \frac{19}{20} ). Thus, ( \frac{3}{4} + \frac{1}{5} = \frac{19}{20} ).
What is 1 sixth plus 3 eighths?
To add ( \frac{1}{6} ) and ( \frac{3}{8} ), we first find a common denominator, which is 24. Converting the fractions, ( \frac{1}{6} ) becomes ( \frac{4}{24} ) and ( \frac{3}{8} ) becomes ( \frac{9}{24} ). Adding these gives ( \frac{4}{24} + \frac{9}{24} = \frac{13}{24} ). Thus, ( \frac{1}{6} + \frac{3}{8} = \frac{13}{24} ).
What is 7 over 9 take away one quarter?
To calculate ( \frac{7}{9} - \frac{1}{4} ), you first need a common denominator, which is 36. Convert the fractions: ( \frac{7}{9} = \frac{28}{36} ) and ( \frac{1}{4} = \frac{9}{36} ). Now subtract: ( \frac{28}{36} - \frac{9}{36} = \frac{19}{36} ). Thus, ( \frac{7}{9} - \frac{1}{4} = \frac{19}{36} ).
What is 2 over 3 of 3 over 7?
To find ( \frac{2}{3} ) of ( \frac{3}{7} ), you multiply the two fractions: [ \frac{2}{3} \times \frac{3}{7} = \frac{2 \times 3}{3 \times 7} = \frac{6}{21}. ] Simplifying ( \frac{6}{21} ) gives ( \frac{2}{7} ). Thus, ( \frac{2}{3} ) of ( \frac{3}{7} ) is ( \frac{2}{7} ).
What 1 over 3 take away 1 over 6?
To subtract ( \frac{1}{6} ) from ( \frac{1}{3} ), first find a common denominator, which is 6. Convert ( \frac{1}{3} ) to ( \frac{2}{6} ). Then, subtract: ( \frac{2}{6} - \frac{1}{6} = \frac{1}{6} ). Therefore, ( \frac{1}{3} - \frac{1}{6} = \frac{1}{6} ).
3 fifths divide 3?
To divide ( \frac{3}{5} ) by 3, you can multiply ( \frac{3}{5} ) by the reciprocal of 3, which is ( \frac{1}{3} ). This gives you ( \frac{3}{5} \times \frac{1}{3} = \frac{3}{15} ). Simplifying ( \frac{3}{15} ) results in ( \frac{1}{5} ). Therefore, ( \frac{3}{5} \div 3 = \frac{1}{5} ).
