example:
13 ---> 1+3=4
135 ---> 1+3+5=8
1.382 OR 0.000 or 2831
int sum_digits (int num) { int sum; sum =0; while (num) { sum += num % 10; num /= 10; } return sum; } Example usage: int main (void) { int i; printf ("Input a 6-digit number: "); scanf ("%6d", &i); printf ("The sum of the digits in %d is: %d\n", i, sum_digits (i)); return 0; }
# includevoid main(){int no,rem=0,sum=0,n; /*declaration*/printf("Enter 2 digit number:");scanf("%d",&no);for(n=1;n
5
Add the last digit plus the sum of all the previous digits. The base case is that if your integer only has a single digit, just return the value of this digit. You can extract the last digit by taking the remainder of a division by 10 (number % 10), and the remaining digits by doing an integer division by 10.
The sum is the total of numbers added together.
What is the sum of greatest 3-digit 4-digit 5digit
sum
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
The digit sum of 45 is calculated by adding its individual digits together. In this case, 4 + 5 equals 9. Therefore, the digit sum of 45 is 9.
None. The sum of one digit can't be twice the size of the digit.
The final sum is 9
9
i am a two digit # my tens digit# is 3 times my ones digit #and the sum of my digit is 12 what am i
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
The sum of the individual digit is itself
1010111 1111100 1011101 and many more