The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
It is halved. coz voltage=current * resistance
When the voltage in a circuit is doubled, the current typically increases, assuming the resistance remains constant according to Ohm's Law (V = IR). If resistance is unchanged, doubling the voltage will result in doubling the current. However, if the circuit components have nonlinear characteristics, the actual change in current may vary. Always consider the specific characteristics of the circuit for precise outcomes.
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.
It is halved. coz voltage=current * resistance
If resistance is doubled in a circuit with constant voltage, Ohm's Law (V=IR) states that current (I) would be halved since the voltage is constant. This is because the relationship between resistance and current is inversely proportional.
If the voltage in a circuit were doubled, the current would also double according to Ohm's Law (I = V/R), assuming the resistance in the circuit remains constant. This is because current is directly proportional to voltage when resistance is held constant.
In a parallel circuit, the total resistance remains the same when the voltage applied is doubled. Each branch in the parallel circuit will experience the same increase in voltage, but their individual resistances will remain constant.
it will cause a Short Circuit
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
When the voltage in a circuit is doubled, the current typically increases, assuming the resistance remains constant according to Ohm's Law (V = IR). If resistance is unchanged, doubling the voltage will result in doubling the current. However, if the circuit components have nonlinear characteristics, the actual change in current may vary. Always consider the specific characteristics of the circuit for precise outcomes.
In an electrical circuit, if resistance is doubled, EMF (measured in volts) stays constant, and current is halved.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.