The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
It is halved. coz voltage=current * resistance
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.
Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.
It is halved. coz voltage=current * resistance
If resistance is doubled in a circuit with constant voltage, Ohm's Law (V=IR) states that current (I) would be halved since the voltage is constant. This is because the relationship between resistance and current is inversely proportional.
If the voltage in a circuit were doubled, the current would also double according to Ohm's Law (I = V/R), assuming the resistance in the circuit remains constant. This is because current is directly proportional to voltage when resistance is held constant.
In a parallel circuit, the total resistance remains the same when the voltage applied is doubled. Each branch in the parallel circuit will experience the same increase in voltage, but their individual resistances will remain constant.
it will cause a Short Circuit
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
In an electrical circuit, if resistance is doubled, EMF (measured in volts) stays constant, and current is halved.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
If the voltage is doubled and the resistance is constant, Ohm's Law states that the current will also double. This is because the relationship between voltage, current, and resistance is linear, and increasing the voltage will directly increase the current flow.