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When a resistor is connected in parallel what happens to the size of current form the battery?
When a resistor is added the current goes down, that is expressed in the equation current= voltage/ resistance
What is added to a circuit to make the current smaller?
The reduction of voltage or the increase of resistance will reduce the current in a circuit.
A 100 ohms resistor carries a maximum current of 400mA what is the minimum power rating this resistor should have?
To find the minimum power rating of a resistor, you can use the formula ( P = I^2 \times R ). Given that the current ( I ) is 400 mA (or 0.4 A) and the resistance ( R ) is 100 ohms, the power is calculated as ( P = (0.4)^2 \times 100 = 16 ) watts. Therefore, the minimum power rating for the resistor should be at least 16 watts to handle the maximum current safely. It's advisable to choose a resistor with a higher rating for added safety and reliability.
What happens to the total resistance of a series circuit when another resistor is added?
Simply put, the purpose of a resistor is to 'resist' the flow of current. Ohm's Law tells us that for a given voltage, the larger the resistance, or value of that resistor, the lower the current that will flow. Ohm's Law states that I (current) = E (voltage) / R (resistance) - where current is measured in amps, voltage is measured in volts and resistance is measured in ohms.
A battery connected to a resistor supplies a current of 4 amps. If another resistor of equal resistance is connected in series with first resistor the current the battery supplies will be how much?
Half that, or 2 amps. The basic rule in circuits is that voltage (E) equals current (I) times resistance (R). Here's how that expression of Ohm's law looks: E= I x R That means that current equals voltage divided by resistance, as is shown here: I = E / R This expression says that resistance is inversely proportional to current (with voltage staying the same). Further, if resistance goes up, current goes down. If resistance doubles (goes up by a factor of 2), which it does in the case specified in the question, then current is cut in half (goes down by a factor of 2). Half of 4 amps is 2 amps, and that's where the answer came from.
When a resistor is connected in parallel what happens to the size of current form the battery?
When a resistor is added the current goes down, that is expressed in the equation current= voltage/ resistance
When happen to the voltage when ressistor added to a circuit?
Just as the name of the component implies, electrical current gets resisted and therefore it diminishes unless an equally, larger voltage difference in that section of the circuit is applied. V=IR Current is inversely proportional to Resistance (when one goes UP, the other goes DOWN) Voltage is directly proportional to Resistance
What is added to a circuit to make the current smaller?
The reduction of voltage or the increase of resistance will reduce the current in a circuit.
If the resistance in the circuit is increased what will happen to the current and voltage?
* resistance increases voltage. Adding more resistance to a circuit will alter the circuit pathway(s) and that change will force a change in voltage, current or both. Adding resistance will affect circuit voltage and current differently depending on whether that resistance is added in series or parallel. (In the question asked, it was not specified.) For a series circuit with one or more resistors, adding resistance in series will reduce total current and will reduce the voltage drop across each existing resistor. (Less current through a resistor means less voltage drop across it.) Total voltage in the circuit will remain the same. (The rule being that the total applied voltage is said to be dropped or felt across the circuit as a whole.) And the sum of the voltage drops in a series circuit is equal to the applied voltage, of course. If resistance is added in parallel to a circuit with one existing circuit resistor, total current in the circuit will increase, and the voltage across the added resistor will be the same as it for the one existing resistor and will be equal to the applied voltage. (The rule being that if only one resistor is in a circuit, hooking another resistor in parallel will have no effect on the voltage drop across or current flow through that single original resistor.) Hooking another resistor across one resistor in a series circuit that has two or more existing resistors will result in an increase in total current in the circuit, an increase in the voltage drop across the other resistors in the circuit, and a decrease in the voltage drop across the resistor across which the newly added resistor has been connected. The newly added resistor will, of course, have the same voltage drop as the resistor across which it is connected.
What would be different about the circuit if a resistor were added in series with the light bulbs?
The total current in the circuit will decrease.
A 100 ohms resistor carries a maximum current of 400mA what is the minimum power rating this resistor should have?
To find the minimum power rating of a resistor, you can use the formula ( P = I^2 \times R ). Given that the current ( I ) is 400 mA (or 0.4 A) and the resistance ( R ) is 100 ohms, the power is calculated as ( P = (0.4)^2 \times 100 = 16 ) watts. Therefore, the minimum power rating for the resistor should be at least 16 watts to handle the maximum current safely. It's advisable to choose a resistor with a higher rating for added safety and reliability.
Why A parallel leg or branch added around an analog meter movement is known as a?
I don't know which one it is a,,,bypass,,,,current loop,,,,shunt,,,wire resistor
What happens to the total resistance of a series circuit when another resistor is added?
Simply put, the purpose of a resistor is to 'resist' the flow of current. Ohm's Law tells us that for a given voltage, the larger the resistance, or value of that resistor, the lower the current that will flow. Ohm's Law states that I (current) = E (voltage) / R (resistance) - where current is measured in amps, voltage is measured in volts and resistance is measured in ohms.
How is resistance added in a series circuit?
Resistance in a series circuit is added by simply connecting resistors end-to-end. This results in the total resistance being the sum of the individual resistances. The current passing through each resistor in a series circuit remains the same.
What information is needed to track the velocity of an ocean current?
vinegar is added to the beaker of baking soda and water. if the reaction is exothermic, what will happen?
Why ohmmeter cannot read the resistance value when current flows through resistor?
An ohmmeter works by sending a DC voltage through the load under test and measuring the current passed. This works from Ohm's law E/R=I, so, for example, a meter with a source E=9v measuring a 10kΩ resistor would sense 0.0009 Amps (or 900µa) passing through the resistor. If there is some other current being passed through the resistor at the same time, there is no way for the meter to accurately account for this current which would be added to (or subtracted from) the sense current supplied by the meter. (This is an oversimplification since the Ohmmeter will actually provide a current-limited voltage source and must account for the series resistance of the meter (in the case of an analog electro-magnetic meter), current-limiting circuit, internal resistance in the meter batteries (if applicable), etc. in order to generate an accurate reading, however, the above describes the general theory of operation).
A battery connected to a resistor supplies a current of 4 amps. If another resistor of equal resistance is connected in series with first resistor the current the battery supplies will be how much?
Half that, or 2 amps. The basic rule in circuits is that voltage (E) equals current (I) times resistance (R). Here's how that expression of Ohm's law looks: E= I x R That means that current equals voltage divided by resistance, as is shown here: I = E / R This expression says that resistance is inversely proportional to current (with voltage staying the same). Further, if resistance goes up, current goes down. If resistance doubles (goes up by a factor of 2), which it does in the case specified in the question, then current is cut in half (goes down by a factor of 2). Half of 4 amps is 2 amps, and that's where the answer came from.
