Using a fuse correctly rated for current but "overrated" for voltage does not present a problem. Current ratings are critical safety issues, and fuses should be replaced with those of the same current rating. But using a fuse with an identical current rating but a higher voltage rating is not a problem. The reason for that lies in what the voltage rating of a fuse is.
Fuses are given a voltage rating to state a maximum voltage in a circuit that they are designed to protect. And the voltage rating has nothing to do with the "normal" operation of the fuse. The fuse carries current when it operates normally, but when something happens and excessive current flows, the fusible link heats up and opens. This is where the voltage rating comes into play. It is possible that a fuse can arc through when it fails. It is the voltage rating that stands in the way of this.
As long as the voltage rating of a circuit is not beyond the voltage rating of the fuse, that fuse will fail safely when it fails. It is acceptable to use a fuse of an equal current rating but a higher voltage rating when replacing a fuse that has failed.
In this case current flows from a high voltage to a lower voltage in a circuit.
A voltage error circuit is called an error amplifier and happens when there are discrepancies between the voltage output and the reference voltage. A current error circuit happens when there is a disruption of flow in an ammeter.
It is halved. coz voltage=current * resistance
Voltage attempts to make a current flow, and current will flow if the circuit is complete. It is possible to have voltage without current, but current cannot flow without voltage. The answer is "yes",voltage remains the same as current moves through the circuit.As the voltage remains constant, current increases in the circuit.
I = E / RCurrent is directly proportional to voltage.If voltage is multiplied by 'X', current will be multiplied by 'X'.If voltage is divided by 'K', current will be divided by 'K'.If voltage is reduced by half, current will be reduced by half.
The current leads the voltage by 90degree....
This statement is correct.
In this case current flows from a high voltage to a lower voltage in a circuit.
A voltage error circuit is called an error amplifier and happens when there are discrepancies between the voltage output and the reference voltage. A current error circuit happens when there is a disruption of flow in an ammeter.
If the load resistance is constant, then increasing the voltage will increase the current by the same proportion -i.e. doubling the voltage will double the current.
After breakdown voltage is reached in a zener diode the current increases drastically.
Voltage remains constant; current increases.
It is halved. coz voltage=current * resistance
the currents path blocks & normal voltage will flow
Correct Answer= "the current will increase"
Voltage attempts to make a current flow, and current will flow if the circuit is complete. It is possible to have voltage without current, but current cannot flow without voltage. The answer is "yes",voltage remains the same as current moves through the circuit.As the voltage remains constant, current increases in the circuit.
Correct. Power is determined by the product of voltage and current (P = V x I). A high voltage with low current has less overall power output compared to a moderate voltage with a moderate current due to the relationship between voltage, current, and power.