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In any conductor, increased current flow will result in voltage drop. This won't have any effect until you reach about 5% of the circuit voltage, at which point your efficiency declines. If the increased current trips the breaker, then your Voltage will be 0

For reference: Vd= (1.732 x K x I x L) / cmil

Vd is Voltage drop in Volts

1.732 is sq rt of 3 for three phase circuits. For two phase or single phase circuits use 2

K is resistance in Ohms of 1cmil, 1ft of conductor.

K=12.9 for copper conductors, 21.2 for aluminum, both at 75 deg C

I is the current (hence, the more current, the more voltage drop)

L is the length of the conductor

cmil is the wire size, or more accurately, cross-sectional area of the conductor

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