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The equation of an inductor is ...

di/dt = V/L

... meaning that the rate of change of current in amperes per second is proportional to voltage and inversely proportional to inductance in henries.

If, for example, you connect a 200 millihenry inductor across a 12 volt battery, the current will increase at a rate of 60 amperes per second.

Now, the question is, can the inductor, conductors, and/or battery handle that? The answer is no. Something is going to fail. The inductor will rather quickly look like a short circuit across the battery.

This example does not take resistance into account. Practical inductors, conductors, and batteries have resistance, and that will place an upper limit on current but, still, this is not an appropriate way to connect an inductor to a battery.

DO NOT TRY IT IN THE LAB - THERE IS RISK OF EXPLOSION.

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What happens when a inductor reaches a steady state?

An inductor looks like a piece of wire to DC. It will thus look like a resistor, and inductor properties do not apply.


How dc supply is applied to field coil in a brush less alternator?

Through a coupled inductor, similar to a transformer, but working on DC instead of AC.


What is the behaviour of inductor for dc supply?

When a DC supply is applied to an inductor, it initially resists changes in current due to its property of self-inductance. As the current starts to flow, the inductor gradually stores energy in its magnetic field. Once the current reaches a steady state, the inductor behaves like a short circuit, allowing the current to flow freely without any opposition. Thus, in the long term, the inductor does not impede DC, allowing it to pass through.


Is it possible to heat coil using dc power supply?

Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.


What happens when dc supply is given to inductor?

The resulting maximum current is limited by the resistance of the inductor. As the current increases from zero to that maximum value, its expanding magnetic field induces a voltage into the inductor which opposes the rise in that current. So, instead of reaching its maximum value instantaneously, it takes some time -determined by the equation:time to maximum current = 5 L / R (seconds)where L = inductance of inductor in henrys, and R = resistance of inductor in ohms.

Related Questions

What happens when a inductor charges and then discharges?

AnswerWhen you connect DC voltage to an inductor, it opposes the passage of current, which generates a voltage pulse the is several times the value of the applied voltage. When you disconnect the voltage, the electromagnetic field inside the inductor collapses and all the energy it stored is released to the circuit in the form of another large pulse, but this time with opposite polarity.Remember:Inductors oppose changes in current and they store energy in an electromagnetic field.Capacitor oppose changes in voltage and they store energy in an electrostatic field.


What happens when the voltage applied to a dc motor is suddenly reduced to half its value?

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A high dc voltage would be applied to test the insulation between the windings.


What happens when a inductor reaches a steady state?

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Will a capacitor lower voltage?

A: As soon as a DC voltage is applied the capacitor is a short or no voltage


How dc supply is applied to field coil in a brush less alternator?

Through a coupled inductor, similar to a transformer, but working on DC instead of AC.


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Could an induction type instrument be used to measure a pulsing DC signal of varying voltage?

Yes. As the DC is pulsed or varied in voltage, it will induce a varying magnetic field which can be detected with another inductor.


What is the behaviour of inductor for dc supply?

When a DC supply is applied to an inductor, it initially resists changes in current due to its property of self-inductance. As the current starts to flow, the inductor gradually stores energy in its magnetic field. Once the current reaches a steady state, the inductor behaves like a short circuit, allowing the current to flow freely without any opposition. Thus, in the long term, the inductor does not impede DC, allowing it to pass through.


Is it possible to heat coil using dc power supply?

Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.


What type of voltage applied during megger test?

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What happens when dc supply is given to inductor?

The resulting maximum current is limited by the resistance of the inductor. As the current increases from zero to that maximum value, its expanding magnetic field induces a voltage into the inductor which opposes the rise in that current. So, instead of reaching its maximum value instantaneously, it takes some time -determined by the equation:time to maximum current = 5 L / R (seconds)where L = inductance of inductor in henrys, and R = resistance of inductor in ohms.