The equation of an inductor is ...
di/dt = V/L
... meaning that the rate of change of current in amperes per second is proportional to voltage and inversely proportional to inductance in henries.
If, for example, you connect a 200 millihenry inductor across a 12 volt battery, the current will increase at a rate of 60 amperes per second.
Now, the question is, can the inductor, conductors, and/or battery handle that? The answer is no. Something is going to fail. The inductor will rather quickly look like a short circuit across the battery.
This example does not take resistance into account. Practical inductors, conductors, and batteries have resistance, and that will place an upper limit on current but, still, this is not an appropriate way to connect an inductor to a battery.
DO NOT TRY IT IN THE LAB - THERE IS RISK OF EXPLOSION.
An inductor looks like a piece of wire to DC. It will thus look like a resistor, and inductor properties do not apply.
Through a coupled inductor, similar to a transformer, but working on DC instead of AC.
When a DC supply is applied to an inductor, it initially resists changes in current due to its property of self-inductance. As the current starts to flow, the inductor gradually stores energy in its magnetic field. Once the current reaches a steady state, the inductor behaves like a short circuit, allowing the current to flow freely without any opposition. Thus, in the long term, the inductor does not impede DC, allowing it to pass through.
Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.
The resulting maximum current is limited by the resistance of the inductor. As the current increases from zero to that maximum value, its expanding magnetic field induces a voltage into the inductor which opposes the rise in that current. So, instead of reaching its maximum value instantaneously, it takes some time -determined by the equation:time to maximum current = 5 L / R (seconds)where L = inductance of inductor in henrys, and R = resistance of inductor in ohms.
AnswerWhen you connect DC voltage to an inductor, it opposes the passage of current, which generates a voltage pulse the is several times the value of the applied voltage. When you disconnect the voltage, the electromagnetic field inside the inductor collapses and all the energy it stored is released to the circuit in the form of another large pulse, but this time with opposite polarity.Remember:Inductors oppose changes in current and they store energy in an electromagnetic field.Capacitor oppose changes in voltage and they store energy in an electrostatic field.
cureent becomes high
A high dc voltage would be applied to test the insulation between the windings.
An inductor looks like a piece of wire to DC. It will thus look like a resistor, and inductor properties do not apply.
A: As soon as a DC voltage is applied the capacitor is a short or no voltage
Through a coupled inductor, similar to a transformer, but working on DC instead of AC.
The reason an AC voltage applied across a load resistance produces alternating current is because when you have AC voltage you have to have AC current. If DC voltage is applied, DC current is produced.
Yes. As the DC is pulsed or varied in voltage, it will induce a varying magnetic field which can be detected with another inductor.
When a DC supply is applied to an inductor, it initially resists changes in current due to its property of self-inductance. As the current starts to flow, the inductor gradually stores energy in its magnetic field. Once the current reaches a steady state, the inductor behaves like a short circuit, allowing the current to flow freely without any opposition. Thus, in the long term, the inductor does not impede DC, allowing it to pass through.
Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.
DC
The resulting maximum current is limited by the resistance of the inductor. As the current increases from zero to that maximum value, its expanding magnetic field induces a voltage into the inductor which opposes the rise in that current. So, instead of reaching its maximum value instantaneously, it takes some time -determined by the equation:time to maximum current = 5 L / R (seconds)where L = inductance of inductor in henrys, and R = resistance of inductor in ohms.