EFF 1 is an abreviated name to classify a specific type of engine believed to be more energy efficient!
depending on 1phase or 3phase voltage motor , the amphere requirement is found outfor 3phase AC motor use this formula: (HP x 746)/(1.73 x E x Eff x PF)for 1phase AC motor : (HP x 746) / (E x Eff x PF)
Not normally. They are sized slightly above the LRA ( locked rotor amps) or the FLA (full load amps) stated on the motor nameplate. The startup current of a motor can be 125-150% of the running load amperage. This depends on the motor, its EFF (efficiency) and the torque requirement of the load.
A 110 watt motor is equal to a 1 amp motor... Versus a 12 amp motor, the 12 is more powerful. You've probably confused 110 watts with volts, as a 1 amp motor could not be used in a vacuum (it's too small).Basically the amount of power is dependant on the amps the motor uses. You only have the spec on 1 motor so we can't answer your question. All vacuum motors are 110 volt.You are trying to compare Apples and Oranges.Amps or Amperage is a measure of electrical current.Watts is a measure of electrical power.When dealing with single phase power, which is most common in residences, the two are related by the following formula:Watts (W) = Volts (V) x Amps (A)Further we can be certain that the voltage is 120V since we are talking about a vacuum cleaner that would plug into a standard 120V household outlet.A motor drawing 12 amps at 120V will produce 1440W under ideal conditions.You can now compare apples to apples. 1440W vs 110W, however all this tells you is that 12amp device generates more power.It dose not conclude that it provides more suction. For this you need to consider the efficiency (eff) of the devices.1440W x eff = suction power110W x eff = suction power
The formula you are looking for is; Amps = HP x 746/1.73 x Volts x %eff x pf. 350 x746/1.73 x 480 x .90 x .90 = 261100/672 = 389 amps. This amperage assumes that the efficiency of the motor is at 90% and the power factor of the motor is also at 90%.
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EFF 1 is an abreviated name to classify a specific type of engine believed to be more energy efficient!
EFF1 is a high efficiency motor. EFF2 is a standard efficiency motor.
remove the steering wheel and use eff-7
depending on 1phase or 3phase voltage motor , the amphere requirement is found outfor 3phase AC motor use this formula: (HP x 746)/(1.73 x E x Eff x PF)for 1phase AC motor : (HP x 746) / (E x Eff x PF)
EFF-Austin was created in 1991.
EFF Pioneer Award was created in 1992.
To calculate the mechanical energy provided by the motor, you need to divide the input energy by the efficiency of the motor. In this case, with 70% efficiency, you would divide 1960 joules by 0.70 to find that the mechanical energy provided would be approximately 2800 joules.
Start with easiest answer- it is 1 hp! 1 hp = 746 watts or 0.746 kw (note that this is the output power of the motor and not the input. The formula used for a 3 phase motor: P = 1.732 x E x I x pf x eff Where: P- Power in watts 1.732- square root of 3 E- voltage I- current pf- power factor eff- efficiency eff = ouput power / input power
It's an abbreviation. .. CEE-EFF-CEE
Serge Elisse eff has written: 'Elementary Japanese for college students'
Not normally. They are sized slightly above the LRA ( locked rotor amps) or the FLA (full load amps) stated on the motor nameplate. The startup current of a motor can be 125-150% of the running load amperage. This depends on the motor, its EFF (efficiency) and the torque requirement of the load.
Eff-a-tha