Vmin, or minimum voltage, is the lowest voltage level required for a device or system to operate correctly and reliably. It is crucial in various applications, including electronics and power systems, to ensure that components function without failure. Operating below Vmin can lead to malfunctions or degraded performance. Understanding Vmin helps in designing circuits and systems for stability and efficiency.
Range = (Vmax -Vmin) = (88-18) =70
The equation for finding the amplitude of a wave is A = (1/2)(Vmax - Vmin), where A is the amplitude, Vmax is the maximum value of the wave, and Vmin is the minimum value of the wave. The amplitude represents the maximum displacement of the wave from its equilibrium position.
%m = Ei/Ec *100 or % m= V max -V min/Vmax+Vmin * 100
Following is the Voltage calculation for a 3 Phase Full wave rectifier bridge circuit with 6 diodes: Vac rms (Ph-Ph input) = 2pi / 3√2 x Vdc (output) Vac rms (Ph-Ph input) = 0.74 x Vdc (output) Hope that helps :) Regards, Syed
Any of these: Voltmeter: Across the Resistor, Vmax when diode conducts, 0 when you switch polarity Across the diode Vmin when conducting, Vmax when not. Ammeter: in series with ckt, Amax when conducting Amin when not, etc. Ohmmeter: No power required. Lo R one way, Hi R when leads reversed
A few more variables need to be factored in: * the speed at which the ball is moving at the top of its path, v. * gravitational field strength, g. * the mass of the ball, m. (The mass of the string is neglected.) The ball's acceleration towards the centre of its circular trajectory is given by v2/r therefore the force required to keep it in this trajectory is mv2/r from Newton's second law of motion. This force is supplied jointly by the weight of the ball, mg, and the tension in the string, T. Therefore T = (mv2/r) - mg The minimum possible value of T is actually zero. This will occur when the ball is moving so slowly that its centripetal force can be supplied entirely by its weight, without pulling on the string. In other words: v2m/r = mg v2/r = g Therefore, to achieve minimum tension use: vmin = sqrt(gr) If the velocity falls below sqrt(gr) the ball will drop inwards from its circular path.
In landing, an aircraft's speed is reduced and a predictable descent angle is established, the vertex being the numbers on the runway. That is to say, you aim the aircraft at the numbers. This invariably requires a decrease in the throttle and engine rpm. Pilots may choose to deploy flaps at this point on aircraft equipped with flaps. Flaps change the aircraft's wing geometry, increasing lift, increasing drag, increasing angle of descent, and lowering stall speed. To land, the aircraft must transition from Vmin (minimum speed required to maintain flight) to a lower, non-flying speed (Vstall). Using flaps helps achieve this end. However, flaps are NOT necessary to land; they're just convenient. Flaps-off landings are made all the time. So you descend to the point where you're just about going to nose it in, then you slowly pull back on the stick, adjusting the throttle if necessary, bleeding off airspeed, watching the ground coming up. It's at this point where you get into what is called "ground effect" where the air is caught between the bottom of the wing and the ground. By and large, it's your friend. You "mush" through the ground effect, continuing to incrementally lift the nose, keeping an eye on airspeed and altitude, while maintaining the aircraft's track in the center of the runway. On high crosswind days, this can be challenging. At the appropriate instant the plane both stalls, and touches down on the runway on the main landing gear. Back pressure on the stick is then released, and you taxi off the runway to parking, using rudder and differential braking.