Apparent Power=Active Power+Reactive Power or Active Power=VI Cos(Phase Angle) Reactive Power=VI Sin(Phase Angle) Apparent Power= VI
Power factor is defined as the ratio of real power over total power. Total power is the vector sum of real and reactive power.
If a load takes 50 kW at a power factor of 0.5 lagging calculate the apparent power and reactive power Answer: Apparent power = Active power / Power Factor In this case, Active power = 50 kW and power factor = 0.5 So Apparent power = 50/0.5 = 100 KVA
Use a wattmeter, as it only reads 'real power' of your load. Use an ammeter and a voltmeter, and the product of the two readings will give you 'apparent power' of your load. Since apparent power is the vector sum of real power and reactive power, use the following equation to find the reactive power of your load: (reactive power)2 = (apparent power)2 - (real power)2
The power is the product between the magnitude of voltage and the magnitude of current. Whereas the power factor is a ratio between the active power and the apparent power.
Will Boast has written: 'Power ballads'
missuse pwer just to show off
missuse pwer just to show off
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The preposition for the word "boast" is "about" or "of." For example, you can boast about your achievements or boast of your accomplishments.
boast
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Russell Boast's birth name is Russell John Boast.
Ghost boast
One may use any of several prepositions with the verb to boast, including:boast of (deeds, exploits)boast about (abilities, charcateristics)boast to (anyone listening)boast among (ones peers, or a group)
Robin Boast was born in 1956.
"I know you did a great job on your exam, but there is no reason for you to boast about it." Boast means the same thing as bragging.