A set which containing $and pi are the end blocks are the finite and without these are infinite
prove that every subset of a finite set is a finite set?
A computer program.
The defining characteristic of FA is that they have only a finite number of states. Hence, a finite automata can only "count" (that is, maintain a counter, where different states correspond to different values of the counter) a finite number of input scenarios.There is no finite automaton that recognizes these strings:The set of binary strings consisting of an equal number of 1's and 0'sThe set of strings over '(' and ')' that have "balanced" parenthesesThe 'pumping lemma' can be used to prove that no such FA exists for these examples.
YES, unit step function is periodic because its power is finite that is 1/2.. and having infinite energy.
The signum signal, defined as ( x(t) = \text{sgn}(t) ), is an example of a power signal rather than an energy signal. This is because it does not have finite energy; its integral over all time diverges. However, its average power can be calculated and is finite, which classifies it as a power signal. In summary, the signum signal is a power signal due to its infinite energy and finite average power.
A finite set has a finite number of elements, an infinite set has infinitely many.
The way I understand it, a finite set can not be an infinite set, because if it were an infinite set, then it would not be a finite set, and the original premise would be violated.
A set which containing $and pi are the end blocks are the finite and without these are infinite
finite
The set of integers is an infinite set as there are an infinite number of integers.
An empty set (null set) is considered finite.
Infinite.
It is called in infinite set.
all finite set is countable.but,countable can be finite or infinite
The set of your friends is finite. The set of counting numbers (part of which you will use to count your friends) is infinite.
infinite
It is called in infinite set.