What is an array to show 4X4?

Answer 1

An array of 4 times 8 is a 2D array with 4 Rows and 8 Columns.

// Declaration of a 2D array [ROWS] [COLUMNS]

int [][] arr = new int[4][8];

// What a 2D Array looks like populated with numbers

//

// _____________________

// Row 0 | 1 0 0 0 0 0 0 7

// Row 1 | 0 0 0 0 0 0 0 0

// Row 2 | 0 0 0 0 0 0 4 0

// Row 3 | 0 0 0 0 0 0 0 0

The example array above has the number 1 place in the first row of the first column.

In the first row of the eight column the number 7 is placed.

In the third row of the seventh column the number 4 is placed.

// Accessing these values

int one = arr[0][0];

int seven = arr[0][7];

int four = arr[2][6];

Answer 2

It is a two-dimensional array of 8x4 elements (32 elements in total). You can also think of it as a one-dimensional array of 8 elements, where each element is itself a one-dimensional array of 4 elements. In other words, an array of arrays. Two-dimensional arrays are best imagined as being a table of rows and columns. An 8x4 array therefore has 8 rows and 4 columns, where each row is an an array of 4 elements.

Answer 3

#include<stdio.h>

int main ()

{

int array[6][4] ={19,43,43,23,30,13};

int i,j;

for(i=0;i<6;i++)

for(j=o;j<4;j++)

printf("array[%d][%d]=%d\n,"i.j.array[i][j]);

return 0;

}

Answer 4

This is the array for 8 times 6:

xxxxxx

xxxxxx

xxxxxx

xxxxxx

xxxxxx

xxxxxx

xxxxxx

xxxxxx Simple.

Answer 5

how does your array show that 4x4 is double 2x4