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Steel rod weight per inch.... this depends on the thickness and shape of the steel rod.
The density of steel is around 500 pounds per cubit foot, so, for example:
If the rod is cylindrical and has a diameter of 1/2 inch, each "inch" of the rod is a cylinder with length L=1. The volume of this cylinder is found with pi*r^2*L.
Since diameter = .5in, radius = .25in.
pi*.25^2*1 = about .2in^3 or 1/5 cubic inch.
Now, a cubic inch is about 5.8*10^-4 cubic feet, so...
500lb/ft^3 * 5.8*10^-4 in^3/ft^3 = .28935 pounds per cubic inch.
We have one fifth cubic inch, so multiply that by .2...
and each inch of our rod weighs .05787 pounds, which is pretty much 3/50 pounds.
Coincidentally, 3/50 of a pound is just about an ounce, so our cylindrical steel rod of diameter 1/2 inch pretty much weighs one ounce per inch!
What else can I help you with?
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