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When ( n ) capacitors of equal capacitance ( c ) are connected in series, the effective or equivalent capacitance ( C_{\text{eq}} ) is given by the formula: [ \frac{1}{C_{\text{eq}}} = \frac{1}{c} + \frac{1}{c} + \ldots + \frac{1}{c} = \frac{n}{c} ] Thus, the effective capacitance is: [ C_{\text{eq}} = \frac{c}{n} ] This shows that the effective capacitance decreases as the number of capacitors in series increases.
If a circuit containing five 50-ohm resistors has a total resistance of 10 ohms, the resistors must be connected in parallel. In a parallel configuration, the total resistance is calculated using the formula ( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} ). For five 50-ohm resistors in parallel, the total resistance indeed comes out to 10 ohms.
A frac tank is used to hold water, or a proppant, when a well is being fractured. The material is held in a frac tank and connected by a hose or pipeline to a pump that will flow it down the wellbore at a high pressure to push open the formation and the proppant is used to keep it open. 21,000-gallon tank, 500 Barrels, for on-site storage of fluids. Also known as: mobile storage tank, portable tank, VE Tank, Baker Tank, Rhino Tank, Rain-for-Rent Tank, E-Tank Frac tank is basically a generic term for mobile steel storage tanks used to hold liquids. Typically used for fracing wells in the oil and gas industry, a frac tank may also be used to store any liquids like run-off water, diesel fuel, glycol, oils, waste products, etc. They are usually 21,000 gallon single wall steel tanks, but are also offered as double wall tanks by Gaurav Associates of India, AFC Tanks, VE Enterprises and Truck Center of Fort Worth Inc. These tanks have a single rear axle to be moved with a winch truck or tractor when empty. The major manufacturers of frac tanks are Gaurav Associates, AFC Tanks, VE Enterprises, Dragon, and Wichita. Alpha Tanks and VE Enterprises make heated Frac Tanks that may be used in cold climates where regular Frac Tanks freeze. Heated water also improves the effectiveness of the fracturing process.
Resistance can be calculated using Ohm's Law, which states that resistance (R) is equal to the voltage (V) across a component divided by the current (I) flowing through it: ( R = \frac{V}{I} ). Additionally, in a circuit with multiple resistors, total resistance can be calculated using series and parallel formulas. For resistors in series, the total resistance is the sum of individual resistances, while for resistors in parallel, the total resistance can be found using the formula ( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \ldots ).
The patented pocket hose, called the Dap Hose was invented by the Dap Company.
A fueler that usually stays on frac sites in a 6500 gallon fuel truck for extended periods of time. This individual is responsible for the fueling of all equipment used to frac a site. The hose on his truck can be as long as 180 feet enabling the fueler to reach the equipment.
To add the mixed numbers (3 \frac{23}{24}) and (2 \frac{3}{4}), first convert (2 \frac{3}{4}) to a fraction: (2 \frac{3}{4} = 2 + \frac{3}{4} = \frac{8}{4} + \frac{3}{4} = \frac{11}{4}). Now, convert (3 \frac{23}{24}) to an improper fraction: (3 \frac{23}{24} = \frac{72}{24} + \frac{23}{24} = \frac{95}{24}). Next, find a common denominator (which is 24) and convert (\frac{11}{4}) to (\frac{66}{24}). Finally, add the fractions: (\frac{95}{24} + \frac{66}{24} = \frac{161}{24}), which simplifies to (6 \frac{13}{24}). Thus, (3 \frac{23}{24} + 2 \frac{3}{4} = 6 \frac{13}{24}).
To add ( \frac{2}{5} ) and ( \frac{2}{7} ), we first find a common denominator, which is 35. Converting the fractions, we have ( \frac{2}{5} = \frac{14}{35} ) and ( \frac{2}{7} = \frac{10}{35} ). Adding these gives ( \frac{14}{35} + \frac{10}{35} = \frac{24}{35} ). Therefore, ( \frac{2}{5} + \frac{2}{7} = \frac{24}{35} ).
To add ( \frac{8}{3} ) and ( -\frac{9}{4} ), first find a common denominator, which is 12. Rewrite the fractions: ( \frac{8}{3} = \frac{32}{12} ) and ( -\frac{9}{4} = -\frac{27}{12} ). Now add them: ( \frac{32}{12} - \frac{27}{12} = \frac{5}{12} ). Therefore, ( \frac{8}{3} + -\frac{9}{4} = \frac{5}{12} ).
To find the sum of ( \frac{3}{4} ) and ( \frac{5}{16} ), first convert ( \frac{3}{4} ) to a fraction with a denominator of 16: ( \frac{3}{4} = \frac{12}{16} ). Now, add ( \frac{12}{16} ) and ( \frac{5}{16} ): ( \frac{12}{16} + \frac{5}{16} = \frac{17}{16} ). Therefore, the sum is ( \frac{17}{16} ) or ( 1 \frac{1}{16} ).
To add ( \frac{3}{4} ) and ( \frac{1}{5} ), first find a common denominator, which is 20. Convert ( \frac{3}{4} ) to ( \frac{15}{20} ) and ( \frac{1}{5} ) to ( \frac{4}{20} ). Now, add the fractions: ( \frac{15}{20} + \frac{4}{20} = \frac{19}{20} ). Thus, ( \frac{3}{4} + \frac{1}{5} = \frac{19}{20} ).
To find ( \frac{2}{3} ) of ( \frac{3}{7} ), you multiply the two fractions: [ \frac{2}{3} \times \frac{3}{7} = \frac{2 \times 3}{3 \times 7} = \frac{6}{21}. ] Simplifying ( \frac{6}{21} ) gives ( \frac{2}{7} ). Thus, ( \frac{2}{3} ) of ( \frac{3}{7} ) is ( \frac{2}{7} ).
To subtract ( \frac{1}{6} ) from ( \frac{1}{3} ), first find a common denominator, which is 6. Convert ( \frac{1}{3} ) to ( \frac{2}{6} ). Then, subtract: ( \frac{2}{6} - \frac{1}{6} = \frac{1}{6} ). Therefore, ( \frac{1}{3} - \frac{1}{6} = \frac{1}{6} ).
To find the sum of ( \frac{8}{9} ) and ( \frac{4}{7} ), first find a common denominator, which is 63. Convert the fractions: ( \frac{8}{9} = \frac{56}{63} ) and ( \frac{4}{7} = \frac{36}{63} ). Now, add them together: ( \frac{56}{63} + \frac{36}{63} = \frac{92}{63} ). Thus, the sum is ( \frac{92}{63} ) or ( 1 \frac{29}{63} ).
To add ( \frac{7}{8} ) and ( \frac{7}{10} ), first find a common denominator, which is 40. Convert the fractions: ( \frac{7}{8} = \frac{35}{40} ) and ( \frac{7}{10} = \frac{28}{40} ). Now, add them together: ( \frac{35}{40} + \frac{28}{40} = \frac{63}{40} ), which can also be expressed as ( 1 \frac{23}{40} ).
Three fractions that add up to one whole are ( \frac{1}{3} ), ( \frac{1}{3} ), and ( \frac{1}{3} ). When you sum these fractions, ( \frac{1}{3} + \frac{1}{3} + \frac{1}{3} = \frac{3}{3} = 1 ). Other combinations, such as ( \frac{1}{2} ), ( \frac{1}{4} ), and ( \frac{1}{4} ), also equal one whole.
To add the fractions ( \frac{2}{3} ) and ( \frac{11}{12} ), first find a common denominator. The least common multiple of 3 and 12 is 12. Convert ( \frac{2}{3} ) to ( \frac{8}{12} ), then add ( \frac{8}{12} + \frac{11}{12} = \frac{19}{12} ). Thus, ( \frac{2}{3} + \frac{11}{12} = \frac{19}{12} ) or ( 1 \frac{7}{12} ).