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What is the lowest resistance that can be obtained by combining four coils of resistors of 4 ohm 8 ohm12ohm and 24 ohm?
To achieve the lowest resistance when combining resistors, you should connect them in parallel. The formula for the total resistance ( R_t ) of resistors in parallel is given by ( \frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} ). For the given resistors (4 ohms, 8 ohms, 12 ohms, and 24 ohms), this results in ( \frac{1}{R_t} = \frac{1}{4} + \frac{1}{8} + \frac{1}{12} + \frac{1}{24} = \frac{13}{24} ), leading to a total resistance ( R_t ) of approximately 1.85 ohms.
What is the total inductance of a circuit that contains two 22 mH inductors in parallel?
To find the total inductance ( L_t ) of two inductors in parallel, you can use the formula: [ \frac{1}{L_t} = \frac{1}{L_1} + \frac{1}{L_2} ] For two identical inductors of 22 mH, this simplifies to: [ \frac{1}{L_t} = \frac{1}{22 , \text{mH}} + \frac{1}{22 , \text{mH}} = \frac{2}{22 , \text{mH}} = \frac{1}{11 , \text{mH}} ] Thus, the total inductance ( L_t ) is 11 mH.
3 inductors connected in parallel. Inductor 1 has an inductance of 0.06 H inductor 2 has an inductance of 0.05 H and inductor 3 has an inductance of 0.1 H. What is the total inductance of this circuit?
When inductors are connected in parallel, the total inductance (L_total) can be calculated using the formula: (\frac{1}{L_{total}} = \frac{1}{L_1} + \frac{1}{L_2} + \frac{1}{L_3}). For the given inductors, this becomes: (\frac{1}{L_{total}} = \frac{1}{0.06} + \frac{1}{0.05} + \frac{1}{0.1}). Calculating this yields (L_{total} \approx 0.017 H) or 17 mH.
When n capacitors of equal capacitances c are connected in series the effective capacitance is?
When ( n ) capacitors of equal capacitance ( c ) are connected in series, the effective or equivalent capacitance ( C_{\text{eq}} ) is given by the formula: [ \frac{1}{C_{\text{eq}}} = \frac{1}{c} + \frac{1}{c} + \ldots + \frac{1}{c} = \frac{n}{c} ] Thus, the effective capacitance is: [ C_{\text{eq}} = \frac{c}{n} ] This shows that the effective capacitance decreases as the number of capacitors in series increases.
If a circuit containing five 50-ohm resistors has a total resistance of 10 ohmthe circuit is a (n)?
If a circuit containing five 50-ohm resistors has a total resistance of 10 ohms, the resistors must be connected in parallel. In a parallel configuration, the total resistance is calculated using the formula ( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} + \frac{1}{R_5} ). For five 50-ohm resistors in parallel, the total resistance indeed comes out to 10 ohms.
What is wet hose fueling?
A fueler that usually stays on frac sites in a 6500 gallon fuel truck for extended periods of time. This individual is responsible for the fueling of all equipment used to frac a site. The hose on his truck can be as long as 180 feet enabling the fueler to reach the equipment.
What is 3 23 plus 2 34?
To add the mixed numbers (3 \frac{23}{24}) and (2 \frac{3}{4}), first convert (2 \frac{3}{4}) to a fraction: (2 \frac{3}{4} = 2 + \frac{3}{4} = \frac{8}{4} + \frac{3}{4} = \frac{11}{4}). Now, convert (3 \frac{23}{24}) to an improper fraction: (3 \frac{23}{24} = \frac{72}{24} + \frac{23}{24} = \frac{95}{24}). Next, find a common denominator (which is 24) and convert (\frac{11}{4}) to (\frac{66}{24}). Finally, add the fractions: (\frac{95}{24} + \frac{66}{24} = \frac{161}{24}), which simplifies to (6 \frac{13}{24}). Thus, (3 \frac{23}{24} + 2 \frac{3}{4} = 6 \frac{13}{24}).
What is 9 12th's plus 2 fourths?
To add ( \frac{9}{12} ) and ( \frac{2}{4} ), first simplify ( \frac{2}{4} ) to ( \frac{1}{2} ) or ( \frac{6}{12} ) for a common denominator. Now, ( \frac{9}{12} + \frac{6}{12} = \frac{15}{12} ). This can be simplified to ( \frac{5}{4} ) or ( 1 \frac{1}{4} ).
What is 2 fifths plus 2 sevenths?
To add ( \frac{2}{5} ) and ( \frac{2}{7} ), we first find a common denominator, which is 35. Converting the fractions, we have ( \frac{2}{5} = \frac{14}{35} ) and ( \frac{2}{7} = \frac{10}{35} ). Adding these gives ( \frac{14}{35} + \frac{10}{35} = \frac{24}{35} ). Therefore, ( \frac{2}{5} + \frac{2}{7} = \frac{24}{35} ).
What is eight thirds plus negative nines forths?
To add ( \frac{8}{3} ) and ( -\frac{9}{4} ), first find a common denominator, which is 12. Rewrite the fractions: ( \frac{8}{3} = \frac{32}{12} ) and ( -\frac{9}{4} = -\frac{27}{12} ). Now add them: ( \frac{32}{12} - \frac{27}{12} = \frac{5}{12} ). Therefore, ( \frac{8}{3} + -\frac{9}{4} = \frac{5}{12} ).
What is 3 fifths plus 3 eighths?
To add ( \frac{3}{5} ) and ( \frac{3}{8} ), first find a common denominator, which is 40. Converting the fractions, ( \frac{3}{5} = \frac{24}{40} ) and ( \frac{3}{8} = \frac{15}{40} ). Adding these together gives ( \frac{24}{40} + \frac{15}{40} = \frac{39}{40} ). Therefore, ( \frac{3}{5} + \frac{3}{8} = \frac{39}{40} ).
What is 3 over 4 plus 1 over 5?
To add ( \frac{3}{4} ) and ( \frac{1}{5} ), first find a common denominator, which is 20. Convert ( \frac{3}{4} ) to ( \frac{15}{20} ) and ( \frac{1}{5} ) to ( \frac{4}{20} ). Now, add the fractions: ( \frac{15}{20} + \frac{4}{20} = \frac{19}{20} ). Thus, ( \frac{3}{4} + \frac{1}{5} = \frac{19}{20} ).
What is 1 sixth plus 3 eighths?
To add ( \frac{1}{6} ) and ( \frac{3}{8} ), we first find a common denominator, which is 24. Converting the fractions, ( \frac{1}{6} ) becomes ( \frac{4}{24} ) and ( \frac{3}{8} ) becomes ( \frac{9}{24} ). Adding these gives ( \frac{4}{24} + \frac{9}{24} = \frac{13}{24} ). Thus, ( \frac{1}{6} + \frac{3}{8} = \frac{13}{24} ).
What is the sum 3 4 plus 5 16?
To find the sum of ( \frac{3}{4} ) and ( \frac{5}{16} ), first convert ( \frac{3}{4} ) to a fraction with a denominator of 16: ( \frac{3}{4} = \frac{12}{16} ). Now, add ( \frac{12}{16} ) and ( \frac{5}{16} ): ( \frac{12}{16} + \frac{5}{16} = \frac{17}{16} ). Therefore, the sum is ( \frac{17}{16} ) or ( 1 \frac{1}{16} ).
What is 7 over 9 take away one quarter?
To calculate ( \frac{7}{9} - \frac{1}{4} ), you first need a common denominator, which is 36. Convert the fractions: ( \frac{7}{9} = \frac{28}{36} ) and ( \frac{1}{4} = \frac{9}{36} ). Now subtract: ( \frac{28}{36} - \frac{9}{36} = \frac{19}{36} ). Thus, ( \frac{7}{9} - \frac{1}{4} = \frac{19}{36} ).
What is 2 over 3 of 3 over 7?
To find ( \frac{2}{3} ) of ( \frac{3}{7} ), you multiply the two fractions: [ \frac{2}{3} \times \frac{3}{7} = \frac{2 \times 3}{3 \times 7} = \frac{6}{21}. ] Simplifying ( \frac{6}{21} ) gives ( \frac{2}{7} ). Thus, ( \frac{2}{3} ) of ( \frac{3}{7} ) is ( \frac{2}{7} ).
What 1 over 3 take away 1 over 6?
To subtract ( \frac{1}{6} ) from ( \frac{1}{3} ), first find a common denominator, which is 6. Convert ( \frac{1}{3} ) to ( \frac{2}{6} ). Then, subtract: ( \frac{2}{6} - \frac{1}{6} = \frac{1}{6} ). Therefore, ( \frac{1}{3} - \frac{1}{6} = \frac{1}{6} ).
