2 to 5% of full load current
Load!
Full load current ofthe motor x 0.58
What does the question refer to? Induction motors? Transformers? For transformers, the no-load voltage is the voltage -- across the secondary or primary -- when there is no load attached to the secondary, that is, when there is no current in the secondary. No-load current really only makes sense when talking about a motor, because current is flowing in the device even when it's not under load. A rule of thumb is the no-load current is about a third to one half the full-load current.
The secondary load current will change. This, in turn, will cause the primary current to change (the primary current being the phasor sum of the [IS (Np/Ns)] and the primary current (Io).
There are various formula of load calculation. Power equals current multiplied by the voltage. Power can also be computed by multiplying the resistance by the square of the current.
The formula you are looking for is I = Watts/ Voltage, I = 3000/voltage.
Basically you apply a voltage to a load (the iron's heating element) which induces a current. The current through the load generates heat according to the formula Power = Current^2 * Resistance.
The secondary current is calculated by dividing the secondary current by the impedance of the load. This value shouldn't exceed the secondary-winding's rated current except for short periods of time.
The load current of an AC circuit depends on various factors such as the voltage of the circuit, the resistance of the load, and the power consumption of the load. It can be calculated using Ohm's Law (I = V / R) or the power formula (P = VI).
For a single-phase system, active (or 'true') power is the product of the supply voltage, the load current, and the power factor of the load.
Load current is related to load resistance by an inverse relationship. The load current increases linearly as load resistance decreases. Remember, the less resistance, the more current.
2 to 5% of full load current
Full load current can be calculated by the formula given below: P=SQUARE ROOT OF 3*V*I*POWER FACTOR P=1.732*V*I*PF suppose 3 kw motor three phase voltage assuming .85 power factor and 415 volt full load current will be 3*1000=1.732*415*I*.85 I=4.9 ampere(full load ampere)
Load!
load
No load current is mostly inductive, hence the load current may not be a sine wave