the maximum amount of current that a forward-biased diode can withstand before burning out or being seriously degraded.
It depends of your panel ratings. usualy, a panel short-circuited has a maximum current, you can base the value on that. But if you are doing an array of panels, you have to pai attention to the parallel connection, once that multiplies the current across the circuit. in this case you have to use diodes that support the current of the array.
Diodes get damaged when their reverse voltage or forward current ratings are exceeded. It is also possible that a high speed transient could exceed the forward voltage rating before the diode turns on, but this is not normally the case. In a car, primarily in the alternator, diodes get damaged by excessive current draw, or by connecting batteries backwards when jump starting. One way to get excessive draw is to attempt to rev the source engine while cranking the target engine - that is not a good idea - you should only rev the source engine when you are trying to add some charge to the target battery - you should let the source engine idle when cranking the target engine.
The factor of 0.707 is used to convert the peak, or maximum voltage or current, into the corresponding root-mean-square (r.m.s.) value. it does not have anything to do with 'bandwidth'.
You have to imagine the internal resistance as being in parallel with any load you connect. You get the maximum possible current when the load is zero. In this case, just apply Ohm's Law. That is, divide the voltage by the internal resistance.
The current is 0. Current is the unit of flow of electrons in a circuit, and in an open circuit, electrons cannot flow. Therefore there is 0 current. Another way to look at it is that I = V / R, where I = Amps (current), V = voltage, and R = resistance (impedance). In an open circuit, the impedance is infinite, and by using our math skills, we know that X (or V in our case) divided by infinity, is 0. I = V / Infinity = 0
It depends of your panel ratings. usualy, a panel short-circuited has a maximum current, you can base the value on that. But if you are doing an array of panels, you have to pai attention to the parallel connection, once that multiplies the current across the circuit. in this case you have to use diodes that support the current of the array.
Presumably you are referring to an a.c. current?If so, then the average value of an a.c. current is zero so, clearly, you cannot determine its maximum value.However, average current is more-usually applied over half a cycle, in which case, for a sinusoidal current, this value is 0.637 Imax. So the maximum current will be the average value, divided by 0.637.
Diodes get damaged when their reverse voltage or forward current ratings are exceeded. It is also possible that a high speed transient could exceed the forward voltage rating before the diode turns on, but this is not normally the case. In a car, primarily in the alternator, diodes get damaged by excessive current draw, or by connecting batteries backwards when jump starting. One way to get excessive draw is to attempt to rev the source engine while cranking the target engine - that is not a good idea - you should only rev the source engine when you are trying to add some charge to the target battery - you should let the source engine idle when cranking the target engine.
To find the maximum current draw, use the formula: current (A) = power (W) ÷ voltage (V). In this case, 2160 watts ÷ 240 volts = 9 amps. Therefore, the appliance can draw a maximum current of 9 amps.
On average, it is around 11mA. Although every case varies.
Diodes are not perfect devices. When current flows through a diode, it offers some resistance. And the resistive characteristic will cause the generation of thermal energy - which is heat. Diodes come in different "flavors" or types, and they also have ratings. These ratings include the amount of current they are capable of carrying, the reverse voltage they can withstand, and some other characteristics. In the case of zener diodes, they have a current rating, a breakdown voltage rating, and a wattage rating that speaks to the amount of heat the package can dissipate. If we look at something like a rectifier diode rated at, say, a hundred amps, it will be stud mounted. Additionally, there will be specifications regarding the size of the heat sink onto which it is fastened. Again, these diodes will generate heat because their forward resistance, while low, is not zero. Even at a fraction of an ohm of resistance, at a hundred amps, there will be some heat generated when the diode conducts. The devices will need to be bolted up to a pretty heavy plate of aluminum to give the heat some place to go.
1. Redundancy: If one diode breaks (in a way that makes it an insulator), the other diode(s) will do the job. In case of that kind of diode breakage the circuit is like an OR-gate: If diode1 OR diode2 OR ... OR diodeN works properly, then the circuit works properly. If it is important to make sure that the diode does not wrongly conduct, then the diodes should be in series. 2. Reducing the forward voltage: In power electronics high currents need to be conducted with parts that are as ideal as possible (concordantly in this case each diode should be able to carry at least the full current, that has to be transferred through the group of diodes, in order to avoid a cascaded cataclysmic thermal runaway due to a decrease of the forward voltage of the overheated diode).
Let's see an example. A current does a complete cycle every 0.02 seconds - that is, if at one moment it is at maximum, 0.02 seconds later, it will be at maximum again. You might also say that it has 50 cycles per second.In this case, the period is 0.02 seconds; the reciprocal is the frequency (50 Hz in this case).
You are, presumably, referring to alternating current, in which case the 'maximum' current is the peak or amplitude of the waveform. The 'average' value of current is zero, because the average value of the first half of each cycle is negated by the average value over the second half of each cycle. This is why a.c. currents and voltages are always expressed in 'root-mean-square' (r.m.s.) values which is the value of an a.c. current that does the same amount of work as a given value of d.c. current. The r.m.s. value for a sinusoidal current (and voltage, as voltage and current are proportional) is 0.707 times the peak or maximum value.
The factor of 0.707 is used to convert the peak, or maximum voltage or current, into the corresponding root-mean-square (r.m.s.) value. it does not have anything to do with 'bandwidth'.
The letter "I" is normally used for direct current, or for the average current in the case of AC. The lower-case version, "i", is used for the instantaneous current, in the case of AC.
You have to imagine the internal resistance as being in parallel with any load you connect. You get the maximum possible current when the load is zero. In this case, just apply Ohm's Law. That is, divide the voltage by the internal resistance.