0
What else can I help you with?
What is the statement that stores the remainder of dividing the variable you by j in a variable named k?
k = you - int (you / j) * j; You can also use, if your language supports the modulus (%) operator... k = you % j;
Mathematical formulation of assignment problem?
Let there be n jobs which are to be assigned to n operators so that one job is assigned to only one operator. i = Index for job, i = 1, 2, … n j = Index for operators, j = 1, 2, … n Cij = Unit cost for assigning job 'i' to operator 'j' 1 if job i is assigned to operator j Xij = 0 Otherwise The objective is to minimize the total cost of assignment. If job I is assigned to operator 1, the cost is (C11X11). Similarly, for job 1, operator 2 the cost is (C12X12). The objective function is: Minimize = ∑ni=1 ∑nj=1 Cij Xij …(1) Since one job (i) can be assigned to any one of the operators, we have following constraint set: ∑ni=1 Xij = 1; for all j;j = 1, 2, ... n …(2) Similarly for each operator, there may be only one assignment of job. For this, the constraint set is: ∑ni=1 Xij = 1; for all i;i = 1, 2, ... n …(3) The non-negativity constraint is: Xij > 0 …(4) Minimize Z = ∑ni=1 ∑nj=1 Cij Xij Subject to ∑ni=1 Xij = 1; for all j;j = 1, 2, ... n ∑nj=1 Xij = 1; for all i;i = 1, 2, ... n Xij > for all i and all j. JANAK RAJ UPRETI TIMT COLLAGE RAJOURI GARDEN NEW DELHI 17/41 WEST PUNJABI BAGH S-6.. 9311864681 WITH ... DINESH GARG...9899558427
Write a program to overload preincrement and postincrement operator?
#include<iostream.h> #include<conio.h> class num { private: int a,b,c,d; publ;ic: num(int j,int k,int m,int l) { a=j; b=k; c=m; d=l; } void show(void); void operator++(); }; void num::show() { cout<<................................................................... } void num::operator++() {++a;++b;++c;++d; } main() { clrscr(); num X(3,2,5,7); cout<<"b4 inc of x"; X.show(); ++X; cout<<"after inc of x"; X.show(); return 0; }
Write the relationship between Impedance Resistance and Reactance using Operator J?
The operator, 'j', is used to indicate a phasor quantity that has been rotated, counterclockwise, through an angle of 90 degrees.So, if (for example) the operator is applied to a voltage U, then it is written as jU, which indicates means that the voltage lies along the vertical positive axis. A further operation by j, results in jjU, or j2 U, which means that the voltage lies along the horizontal negative axis -so, j2 is equivalent to -1U (or j is equivalent to the square-root of -1) or, simply, -U.A further operation by j, results in the voltage lying along the negative vertical axis: that is: jjjU = jj2U=-jU.But to answer your question, for inductive reactance (XL), we express impedance (Z) a follows: Z = R+jXL and, for capacitive reactance (XC), we express impedance as Z = R - jXC (the L and C should be subscripts).Strictly-speaking the operator j doesn't actually apply to impedance, because impedance, resistance, and reactance or not phasor (vector) quantities. So if we wanted to be strictly accurate, the above equations should be written as:(E/I) = (UR/I) + j (UL/I) and (E/I) = (UR/I)- j (UC/I)...but this is being rather pedantic.
Without using mod operator find the even or odd?
import java.util.*; class Demo { public static void main(String args[]) { System.out.println("Even Numbers Are "); for (int i=1;i<=20;i++) { System.out.print(" "+(2*i)); } System.out.println("\n \n Odd Numbers Are "); for(int j=0;j<=20;j++) { System.out.print(" "+((2*j)+1)); } } }
What has the author D J Bradley written?
D. J. Bradley has written: 'THE OPERATOR'
What has the author J Draper written?
J. Draper has written: 'The application of information theory to human operator problems'
What is the statement that stores the remainder of dividing the variable you by j in a variable named k?
k = you - int (you / j) * j; You can also use, if your language supports the modulus (%) operator... k = you % j;
What is the function of operator 'j' in alternating current?
The operator 'j' represents the imaginary unit in alternating current circuits. It is used to denote the phase difference or angular displacement between voltage and current waveforms in complex impedance calculations. The use of 'j' helps in simplifying mathematical calculations in AC circuits by treating the impedance as a complex number.
What is i plus 1 operator in C plus plus?
The increment operator in C++ is defined by operator++(). All arithmetic types (char, int, float, double, long, short, long long and long double) and all pointer types except void* are supported by operator++(). User-defined types can overload operator++() to provide support where required. operator++() has two versions, prefix increment and postfix increment. Prefix increment behaves as one would expect, incrementing the operand by 1 and returning the modified value. Postfix increment also increments the operand, however, the return value is the pre-incremented value. To understand the difference between prefix and postfix, consider the following: int i = 0; int j = ++i; // i=1, j=1 int i = 0; int j = i++; // i=1, j=0
What is difference between equals and equals equals operators?
The equals operator is used for assigning a value to a variable. ex String name = "efu"; the equals equals operator is used for comparaing if the given value is equal to another value which is assigned for a variable. ex int i = 0; int j = 5; if( i == 0){ System.out.println(j+"can't be divided by"+i); }else{ System.out.println("answer is " +j/i); }
What education is needed to become a carnival worker?
None whatsoever. However, if you can, a class-J cotton candy device operator certification can help.
What has the author I J Maddox written?
I. J. Maddox has written: 'Elements of functional analysis' -- subject(s): Functional analysis 'Infinite matrices of operators' -- subject(s): Infinite matrices, Operator theory, Summability theory
What are different types of operators?
The different types of operators are as follows: *Arithmatic operator *Relational operator *Logical operator *Assignment operator *Increment/Decrement operator *Conditional operator *Bitwise operator *Special operator
Mathematical formulation of assignment problem?
Let there be n jobs which are to be assigned to n operators so that one job is assigned to only one operator. i = Index for job, i = 1, 2, … n j = Index for operators, j = 1, 2, … n Cij = Unit cost for assigning job 'i' to operator 'j' 1 if job i is assigned to operator j Xij = 0 Otherwise The objective is to minimize the total cost of assignment. If job I is assigned to operator 1, the cost is (C11X11). Similarly, for job 1, operator 2 the cost is (C12X12). The objective function is: Minimize = ∑ni=1 ∑nj=1 Cij Xij …(1) Since one job (i) can be assigned to any one of the operators, we have following constraint set: ∑ni=1 Xij = 1; for all j;j = 1, 2, ... n …(2) Similarly for each operator, there may be only one assignment of job. For this, the constraint set is: ∑ni=1 Xij = 1; for all i;i = 1, 2, ... n …(3) The non-negativity constraint is: Xij > 0 …(4) Minimize Z = ∑ni=1 ∑nj=1 Cij Xij Subject to ∑ni=1 Xij = 1; for all j;j = 1, 2, ... n ∑nj=1 Xij = 1; for all i;i = 1, 2, ... n Xij > for all i and all j. JANAK RAJ UPRETI TIMT COLLAGE RAJOURI GARDEN NEW DELHI 17/41 WEST PUNJABI BAGH S-6.. 9311864681 WITH ... DINESH GARG...9899558427
Write a program to overload preincrement and postincrement operator?
#include<iostream.h> #include<conio.h> class num { private: int a,b,c,d; publ;ic: num(int j,int k,int m,int l) { a=j; b=k; c=m; d=l; } void show(void); void operator++(); }; void num::show() { cout<<................................................................... } void num::operator++() {++a;++b;++c;++d; } main() { clrscr(); num X(3,2,5,7); cout<<"b4 inc of x"; X.show(); ++X; cout<<"after inc of x"; X.show(); return 0; }
Write the relationship between Impedance Resistance and Reactance using Operator J?
The operator, 'j', is used to indicate a phasor quantity that has been rotated, counterclockwise, through an angle of 90 degrees.So, if (for example) the operator is applied to a voltage U, then it is written as jU, which indicates means that the voltage lies along the vertical positive axis. A further operation by j, results in jjU, or j2 U, which means that the voltage lies along the horizontal negative axis -so, j2 is equivalent to -1U (or j is equivalent to the square-root of -1) or, simply, -U.A further operation by j, results in the voltage lying along the negative vertical axis: that is: jjjU = jj2U=-jU.But to answer your question, for inductive reactance (XL), we express impedance (Z) a follows: Z = R+jXL and, for capacitive reactance (XC), we express impedance as Z = R - jXC (the L and C should be subscripts).Strictly-speaking the operator j doesn't actually apply to impedance, because impedance, resistance, and reactance or not phasor (vector) quantities. So if we wanted to be strictly accurate, the above equations should be written as:(E/I) = (UR/I) + j (UL/I) and (E/I) = (UR/I)- j (UC/I)...but this is being rather pedantic.
