Pointer overloading is another name for polymorphism. You declare a class virtual and then derive some classes from it. You delare a pointer to the base class and, at run time, assign a value to that pointer that refers to any of the classes in the derivation hierarchy. Deferencing that pointer, then, will properly choose the correct method based on which type of class was used, at run time.
This works because each class type that is virtual contains a static v-table of methods that is used to choose the actual method to use at run time.
Binary operators require two operands (l-value and r-value) and therefore require two arguments when overloading via external functions. When overloading class member operators, the l-value is the class instance itself (the implicit this pointer), therefore only the r-value need be given as an argument.
Java does not support opperator overloading, so the answer to your question is: none.
Example: int x; -- integer int *px= &x; -- pointer to integer int **ppx= &px; -- pointer to pointer to integer int ***pppx= &ppx; -- pointer to pointer to pointer to integer
The this pointer is used to refer to the object that is foremost in the current scope. It has three primary purposes. First, a programmer uses this to refer to a member variable that has been shadowed by a function argument. Secondly, it is used to obtain a reference to itself, usually for the purpose of passing itself to another function or class. Finally, the this pointer can be used to call alternate constructors of the same object, usually as a means of reusing code and providing various constructors with default arguments.
Pointer to Pointer is a double pointer, denoted by (**). Pointer stores the address of the variable and pointer to pointer stores the address of a pointer variable and syntax can be given as int **ptr2ptr;
Overloading refers to defining multiple functions of the same name with different numbers/types of parameters. So no, you cannot overload a pointer.
Binary operators require two operands (l-value and r-value) and therefore require two arguments when overloading via external functions. When overloading class member operators, the l-value is the class instance itself (the implicit this pointer), therefore only the r-value need be given as an argument.
Java does not support opperator overloading, so the answer to your question is: none.
1. pointer to a constant means you can not change what the pointer points to 2. constant pointer means you can not change the pointer.
Example: int x; -- integer int *px= &x; -- pointer to integer int **ppx= &px; -- pointer to pointer to integer int ***pppx= &ppx; -- pointer to pointer to pointer to integer
A pointer only holds an address information (location) in the memory. if a pointer holds points another pointer then it is a pointer to an other pointer. Pointer holds an address in the memory so in that address there is an other location information that shows another location.
No. Operator and/or function overloading is only a C++ thing.
The this pointer is used to refer to the object that is foremost in the current scope. It has three primary purposes. First, a programmer uses this to refer to a member variable that has been shadowed by a function argument. Secondly, it is used to obtain a reference to itself, usually for the purpose of passing itself to another function or class. Finally, the this pointer can be used to call alternate constructors of the same object, usually as a means of reusing code and providing various constructors with default arguments.
pointer is the variable that holds the address of another variable
When we are initializing our object with different internal state then we can use the constructor overloading.
Double (**) is used to denote the double pointer. As we know the pointer stores the address of variable, Double pointer stores the address of any pointer variable. Declaration : int **ptr2Ptr;
Double pointer is a pointer to a pointer. So you can work with the double pointer as you work with a single one.Or you might mean 'pointer to double', eg:void clear_double (double *dp){*dp = 0;}