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The power P dissipated by a resistor will leave the resistor in the form of thermal energy (heat). It will get hot due to the fact that the material it is made of opposes current flow, and when current is forced through it by a voltage source, it gets hot in response. Resistance R could be thought of as "electrical friction" in many cases. Resistance is measured in ohms, voltage V in volts and current I in amperes (amps). The power in watts dissipated by a resistor with the value R will be the square of the current through it times its resistance. P=I2R The power in watts dissipated by a resistor with the value R will be the square of the voltage drop across it divided by its resistance. P=V2/R Because E means energy we take V for voltage. The power in watts dissipated by a resistor with the value R will be the voltage drop across it times the current flow through it. P=IV All three statements are true, and they all say the same thing. The mathematician might say that the variable P is being expressed in terms of the variables I, V and R. As all the statements are true, it can be said that P=I2R=V2/R=IV.
What else can I help you with?
What happens to power dissipation of value of electric current passing through a conductor of constant resistance is doubled?
Power dissipation in a conductor is given by the formula ( P = I^2 R ), where ( P ) is power, ( I ) is the electric current, and ( R ) is the resistance. If the electric current is doubled, the new current becomes ( 2I ). Substituting this into the power formula results in ( P' = (2I)^2 R = 4I^2 R ), which shows that the power dissipation increases by a factor of four. Therefore, doubling the current through a constant resistance results in a fourfold increase in power dissipation.
What is a resistor bank?
In simple way resistor bank contains number of resistors in series or parallel combination. They are connected in parallel to decrease the resistance and increase current rating and power dissipation.And they are connected in series to increase resistance and power dissipation.
Why does less resistance dissipate more power?
Less resistance dissipates more power because power loss in a resistor is calculated using the formula ( P = I^2R ), where ( P ) is power, ( I ) is current, and ( R ) is resistance. When resistance is lower, for a given voltage, the current increases (Ohm's Law: ( V = IR )), leading to a higher power dissipation. Additionally, lower resistance allows for more efficient energy transfer, resulting in greater power being converted to heat or work rather than being lost in the resistance itself.
What is the power dissipation for TTL?
power dissipation of a logic circuit is usually defined as the supply power required for the gate to operate with a 50% duty cycle at a specific frequency.
Why power dissipation occur?
Power dissipation occurs when electrical energy is converted into heat due to the resistance present in a circuit. When current flows through a resistor, some energy is lost as heat due to collisions between charge carriers and atoms in the material, described by Joule's law. This phenomenon is critical in electronic components, where excessive power dissipation can lead to overheating and potential failure. Proper thermal management is essential to mitigate these effects and ensure the reliability of electronic devices.
What is the relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit, as represented by the equation Pi2r?
The relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit is represented by the equation Pi2r. This equation shows that power dissipation is directly proportional to the square of the current and the resistance in the circuit.
What is the relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit, as represented by the equation P i2r?
The relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit is represented by the equation P i2r. This equation shows that power dissipation is directly proportional to the square of the current and the resistance in the circuit.
What happens to power dissipation of value of electric current passing through a conductor of constant resistance is doubled?
Power dissipation in a conductor is given by the formula ( P = I^2 R ), where ( P ) is power, ( I ) is the electric current, and ( R ) is the resistance. If the electric current is doubled, the new current becomes ( 2I ). Substituting this into the power formula results in ( P' = (2I)^2 R = 4I^2 R ), which shows that the power dissipation increases by a factor of four. Therefore, doubling the current through a constant resistance results in a fourfold increase in power dissipation.
What are the different types of power dissipation?
static power dissipation dynamic power dissipation short circuit power dissipation
What is a resistor bank?
In simple way resistor bank contains number of resistors in series or parallel combination. They are connected in parallel to decrease the resistance and increase current rating and power dissipation.And they are connected in series to increase resistance and power dissipation.
Why does less resistance dissipate more power?
Less resistance dissipates more power because power loss in a resistor is calculated using the formula ( P = I^2R ), where ( P ) is power, ( I ) is current, and ( R ) is resistance. When resistance is lower, for a given voltage, the current increases (Ohm's Law: ( V = IR )), leading to a higher power dissipation. Additionally, lower resistance allows for more efficient energy transfer, resulting in greater power being converted to heat or work rather than being lost in the resistance itself.
What is the power dissipation for a100Kohm resistor with ten volts going through it?
One milliwatt. Voltage is amperes times resistance, and watts is voltage times current.
What is the difference between power consumption and power dissipation?
A: POWER consumption is total power usage power dissipation is wasted power in the form of heat, IR drop and so on.
Why does largest R dissipate more power?
That's not always the case. One formula for power dissipated is:P = IRSo, a higher resistance means that more power is dissipated - if the current is the same. The reason for this is precisely that resistance is related to the conversion of electrical energy into heat.However, if you put a higher resistance across a specific voltage, you'll get less power dissipation, not more, since less current will flow at a higher resistance.
How do you explain the MOSFET power dissipation?
It will make more sense if you first study the construction of MOSFET. It has three terminals, Gate (G), Source (S), and Drain (D). G is insulated from the S and D. Between S and D is a variable resistor, whose resistance depends on the voltage applied across G and S. Since SD is basically a resistor, you have power dissipation when a voltage is applied across S and D. Power dissipation = Vds * Ids.
What is the power dissipation for TTL?
power dissipation of a logic circuit is usually defined as the supply power required for the gate to operate with a 50% duty cycle at a specific frequency.
What makes a current lower and generates more heat?
The resistance of the electrical conductor, eg a wire, reduces the current which can flow in the circuit. The remaining current which does flow generates heat, representing the electrical energy which has been lost in overcoming the resistance.
